If the magnetic field strength is found to be zero between the two wires at a distance of 3.0 cm from the first wire, what is th
e magnitude of the current in the second wire?
1 answer:
Answer: The magnitude of the current in the second wire 2.67A
Explanation:
Here is the complete question:
Two straight parallel wires are separated by 7.0 cm. There is a 2.0-A current flowing in the first wire. If the magnetic field strength is found to be zero between the two wires at a distance of 3.0 cm from the first wire, what is the magnitude of the current in the second wire?
Explanation: Please see the attachments below
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As per given condition of point B we can see that height at point B is "h/2" from the ground
So we know that potential energy is given as
U = mgh
so here we have to put height h = h/2
so potential energy is U = mgh/2
now for kinetic energy we need to find the speed of it after falling the distance h/2
now by kinematics we will have
now for kinetic energy
now total energy will be given as
now for point C we can say that it is the point near to ground
So here height is ZERO
now potential energy will also be zero
U = 0
now for kinetic energy we need to find speed
now kinetic energy
now again we have total energy
Answer: D. The force and displacement are in the same direction.
Explanation:
The Work done by a Force
refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path with distance
.
Work is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy).
Now, when the applied force is constant and the direction of the force and the direction of the displacement are <u>parallel</u>, the equation to calculate it is:
(1)
When they are not parallel, both directions form an angle, let's call it . In that case the expression to calculate the Work is:
(2)
When the force and displacement are perpendicular to each other, and <u>no work is done</u>.