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kherson [118]
3 years ago
12

a car moving east at 45 km/h turns and travels west at 30 km/h. What is the magnitude and direction of the change in velocity?

Physics
2 answers:
slega [8]3 years ago
7 0

Answer:

The magnitude and direction of the change in velocity is 75 m/s in west.

Explanation:

Given that,

Velocity of car = 45 km/h in east

Velocity of car = 30 km/h in west

We need to calculate the magnitude of the change in velocity

Using formula of change in velocity

Change in velocity = final velocity - initial velocity

\Delta v=V_{f}-v_{i}

Put the value into the formula

\Delta v=-30-45

|\Delta v|=75\ m/s

The direction of the the change in velocity is toward west.

Hence, The magnitude and direction of the change in velocity is 75 m/s in west.

PSYCHO15rus [73]3 years ago
3 0
Magnitude of change is 15km/h
change in direction is to the right?
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Answer:

-112.876J

Explanation:

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Here's a balanced equation for the reaction:

16KNO_3(s) + 24C(s) + S_8(s)    \to 24CO_2(g) + 8N_2(g) + 8K_2S(s)

Let us define P - V work as;

w_{pv} = - P_{external}  \triangle Volume

where  \triangle (Volume) = (V_{final} - V_{initial})

External pressure is given as  1.00atm , therefore the work solely depends on the change in volume and since the reactants are solids, none of the reactants contribute to the volume. Hence,  V_i = 0.

To find the volume of the products, we need to first find the amount of moles of the product made from  2.40_gKNO_3, using the molar mass of  KNO_3  which is 101.1032 g/mol  

2.40_gKNO_3 . {\frac{1molKNO_3}{101.1032_g}} = 0.0237molKNO_3

Now let us convert moles of  KNO_3  into moles of CO_2 and N_2  using the stoichiometric ratios from our balanced equation of the reaction.

0.0237molKNO_3 . {\frac{24molCO_2}{16molKNO_3}} = 0.0356molCO_2

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We will now proceed to convert grams into volume using the density values provided.

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