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kvasek [131]
3 years ago
13

As we increase the frequency of this light, but do not vary anything else (there may be more than one correct answer),

Physics
1 answer:
solong [7]3 years ago
7 0
The answer is c hope this helps
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What can one say about the image produced by a thin lens that produces a positive magnification?
Dafna11 [192]

Answer:

The image is virtual and upright

Explanation:

The magnification of a lens can be written as follows:

M=\frac{y'}{y}=-\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the location of the image with respect to the lens

p is the location of the object with respect to the lens

In this situation, the magnification is positive. This means that:

- y' (the image) has same sign as y (the object) --> the image is upright (same orientation as the object)

- q has opposite sign to p --> this means that the image is located on the same side as the object, so it is a virtual image

5 0
3 years ago
Jack is testing how sound travels. Damon stood on the opposite side of the room and whispered a sentence to him. Then, Jack held
34kurt
D) Sound travels better through the compact molecules of air inside the balloon than the less compact molecules on the outside.
6 0
3 years ago
Read 2 more answers
What causes waves to slow down: change in wave’s wavelength or change in its frequency and y?
Mashutka [201]

Answer:

Although the wave slows down, its frequency remains the same, due to the fact that its wavelength is shorter. When waves travel from one medium to another the frequency never changes.

3 0
3 years ago
In this circuit (see picture), which resistor will draw the least power?
Basile [38]
A few different ways to do this: 

Way #1: 
The current in the series loop is  (12 V) / (total resistance) . 
(Turns out to be 2 Amperes, but the question isn't asking for that.)

In a series loop, the current is the same at every point, so it's
the same current through each resistor.

The power dissipated by a resistor is  (current)² · (resistance),
and the current is the same everywhere in the circuit, so the
smallest resistance will dissipate the least power.  That's  R1 .

And by the way, it's not "drawing" the most power.  It's dissipating it.

Way #2:
Another expression for the power dissipated by a resistance is

                 (voltage across the resistance)²  /  (resistance)  .

In a series loop, the voltage across each resistor is

          [ (individual resistance) / (total resistance ] x battery voltage.

So the power dissipated by each resistor is

         (individual resistance)² x [(battery voltage) / (total resistance)²]

This expression is smallest for the smallest individual resistance.
(The other two quantities are the same for each individual resistor.)
So again, the least power is dissipated by the smallest individual resistance.
That's R1 .                                      

Way #3:  (Einstein's way)
If we sat back and relaxed for a minute, stared at the ceiling, let our minds
wander, puffed gently on our pipe, and just daydreamed about this question
for a minute or two, we might have easily guessed at the answer.

===>  When you wire up a battery and a light bulb in series, the part
that dissipates power, and gets so hot that it radiates heat and light, is
the light bulb (some resistance), not the wire (very small resistance).
3 0
3 years ago
Acceleration is caused by a force acting on a mass.​
Mumz [18]

Answer:

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Explanation:

ples give a crown

4 0
4 years ago
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