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SpyIntel [72]
3 years ago
10

I need help in balancing chemical equations

Chemistry
1 answer:
Mashcka [7]3 years ago
3 0
I can help. First you want to write out each reactant and product with enough space to write in coefficients. Then box the reactants and products to emphazise how the elements shouldnt change. Afterwards, draw a line in front of the box for you to write in the coefficients.Now we srart balancing. To make things easier, you should always follow the method of : (Metals, Nonmetals,Oxygen,Hydrogen) in that order. By balancing each elememt/chemical this way it should make balancing them easier.
So to acryally perform it you're going to look at your first element (while still following the method) and then look over onto the other side to see what coefficient to place. Then after that element is balanced, you move onto the next element. Remember that everytime you balance an element, start over to make sure all of the other elements are still balanced before proceeding.
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How is the sun classified​
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Explanation:

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3 years ago
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You are given an unknown mixture containing NaCl and NaHCO3. When you carry out the heating exactly as described in part A, only
SOVA2 [1]

Answer:

1.52g NaHCO3 were in the original mixture.

Mass percent: 64.1%

Explanation:

When NaHCO3 heats it descomposition occurs as follows:

2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g).

The loss in mass is because of the evaporization of CO2 and H2O. As both are in the same porportion, its molar mass is the sum of both compounds (44g/mol + 18g/mol = 62g/mol)

Loss in mass: 74.80g - 74.24g = 0.56g.

In moles:

0.56g * (1mol / 62g) = 0.00903 moles of gas.

As 1 mole of the gases comes from 2 moles of NaHCO3:

<em>Moles NaHCO3:</em>

0.00903 moles of gas * (2 moles NaHCO3 / 1 mole gas) = 0.018 moles NaHCO3.

In grams (Molar mass NaHCO3: 84g/mol):

0.018 moles NaHCO3 * (84g / mol) = 1.52g NaHCO3 were in the original mixture.

The mass of the mixture was:

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That means mass percent of NaHCO3 is:

(1.52g /  2.372g) * 100 =  64.1%

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3 years ago
The most common isotopic forms of hydrogen are ordinary hydrogen (1H) and deuterium (2H), which have percent compositions of 99.
Alborosie

Answer:

0. 000115

Explanation:

A percentage is defined as a ratio with a basis of 100 as total substance. Convert a percentage to decimal implies to divide the percentage in 100 because decimal form has as basis 1.

For the isotopic forms:

1H: 99.98% → As percent.

99.98% / 100 = 0.9998 → As decimal form.

2H: 0.0115% → As percent.

0.0115% / 100 = <em>0. 000115</em>→ As decimal form.

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Answer:

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Explanation:

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