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Fittoniya [83]
3 years ago
12

A civil engineer plans to design a curved ramp such that a car may not have to rely on friction to round the curve without skidd

ing. The roadway is tilted toward the inside of the curve. Suppose the designated speed is v and the radius of the curve is R. At what angle should the curve be tilted?

Physics
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:\theta =\tan ^{-1}(\frac{v^2}{gR})

Explanation:

let \theta be the inclination at which curve is tilted

v is the speed of car and R is the radius of curve

m is the mass of car

Suppose R is the reaction offered by road to car

Resolving R in x and y direction we get

R\cos \theta will balance weight and R\sin \theta will provide the necessary centripetal Force

thus R\sin \theta =\frac{mv^2}{R}  ------------1

R\cos \theta =m g  ----------------2

Divide 1 & 2 we get

\frac{R\sin \theta }{R\cos \theta }=\frac{mv^2}{mgR}

\tan \theta =\frac{v^2}{gR}

\theta =\tan ^{-1}(\frac{v^2}{gR})                                      

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The closely packed cones in the fovea of the eye have a diameter of about 2 μm. For the eye to discern two images on the fovea
Marina CMI [18]

Answer:

The distance between the object is l=0.0056\  cm

Explanation:

The free body diagram of this setup is on the first uploaded image

From the question

   The diameter of closely packed cones in the fovea of the eye is  =  2 \mu m

     The distance of separation by one cone(not excited ) is d = 4\mu m = 4*10^{-4}cm

     The distance between the two point-like object  is  l

     The diameter of the eye is D = 2 cm

     The distance of the two point-like object from the near point of the eye is A = 28 cm

 From the diagram we see that the light from the two point-like object form a triangle of similar base l and d  and height D and A

So for a triangle with similar base we have that

                \frac{l}{A} =\frac{d}{D}

                \frac{l}{28} = \frac{4*10^{-4}}{2}

making l the subject we have

            l = \frac{28 *4*10^{-4}}{2}

              l=0.0056\  cm

               

         

       

   

5 0
3 years ago
Read 2 more answers
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