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3 years ago

What is mechanical waves

Physics

2 answers:

LuckyWell [14K]3 years ago

6 0

Mechanical waves are those waves that require a material medium for propagation.

<h3>What are mechanical waves?</h3>

Generally, we define a wave as a disturbance along a medium which transfers energy. It then follows that waves move energy from one point to another.

Waves can be classified as;

Mechanical waves
Electromagnetic waves

Mechanical waves are those waves that require a material medium for propagation such as sound, and waves on a strings.

Learn more about mechanical waves: brainly.com/question/9242091

blondinia [14]3 years ago

6 0

Answer:

A mechanical wave is a wave that is not capable of transmitting its energy through a vacuum. Mechanical waves require a medium in order to transport their energy from one location to another.

A sound wave is an example of a mechanical wave.

hope helps~

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At a certain distance from the center of the Earth, a 0.4-kg object has a weight of 2.0 N. (a) Find this distance. (b) If the ob

Alika [10]

Answer:

a) The distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object is 5 m/s².

Explanation:

a) The distance can be found using the equation of gravitational force:

$F = \frac{GMm}{r^{2}}$

Where:

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

M: is the Earth's mass = 5.97x10²⁴ kg

m: is the object's mass = 0.4 kg

F: is the force or the weight = 2.0 N

r: is the distance =?

The distance is:

$r = \sqrt{\frac{GMm}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.97 \cdot 10^{24} kg*0.4 kg}{2.0 N}} = 8.92 \cdot 10^{6} m$

Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object can be calculated knowing the weight:

$W = ma$

Where:

W: is the weight = 2 N

a: is the initial acceleration =?

$a = \frac{W}{m} = \frac{2 N}{0.4 kg} = 5 m/s^{2}$

Therefore, the initial acceleration of the object is 5 m/s².

I hope it helps you!

4 0

3 years ago

A heavy piece of hanging sculpture is suspended by a90-cm-long, 5.0 g steel wire. When the wind

Yuliya22 [10]

As we know that fundamental frequency is given as

$f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}$

here we know that

$\mu = \frac{m}{l}$

here we have

m = mass of wire = 5 g

l = length of wire = 90 cm

$\mu = \frac{0.005}{0.90} kg/m$

$\mu = 5.56 \times 10^{-3} kg/m$

from above formula now

$80 = \frac{1}{2(0.90)}\sqrt{\frac{T}{5.56\times 10^{-3}}}$

$144 = \sqrt{180 T}$

$T = 115.2 N$

now we know that tension is due to weight of the sculpture so we will have

$Mg = 115.2 N$

$M = 11.76 kg$

so its mass will be 11.76 kg

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4 years ago

A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is fo

Alex787 [66]

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:

$R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)$

At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:

$R = \rho* \frac{L}{A} (2)$

The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:

$A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)$

Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:

$\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m$

ρ = 1.6*10⁻⁸ Ω/m

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3 years ago

An object experiences a 8.9 N force and accelerates 6 m/sec2. What is the object's

Inessa [10]

b stupidrwfs

planation:

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3 years ago

What is the energy Q released when 131 53Idecays and 131 54Xe is formed? The atomic mass of 131 53I is 130.906118 u and the atom

DanielleElmas [232]

Answer:0.967meV

Explanation:

-Find the difference in u, so 130.906118-130.90508= 0.001038u

- convert to meV

1 u = 931.494meV

multiply 0.001038 by 931.494

=0.001038 X 931.494

0.967 meV

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4 years ago