Calculate the magnitude of the acceleration of Io due to the gravitational force exerted by Jupiter. [Show all work, including t
1 answer:
The magnitude of the acceleration due to the gravitational force exerted by Jupiter is 25.91 m/s².
<h3>What is acceleration due to gravity?</h3>
- This is the acceleration of a body under a free fall due to influence of gravity.
The magnitude of the acceleration due to the gravitational force exerted by Jupiter is calculated as follows;
where;
- M is mass of Jupiter
- R is the radius of Jupiter
- G is universal constant
Thus, the magnitude of the acceleration due to the gravitational force exerted by Jupiter is 25.91 m/s².
Learn more about acceleration due to gravity here: brainly.com/question/88039
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Answer:
the rate of the change of the length of the shadow is - 0.8625 m/s.
The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.
Explanation:
Given the data in the question;
Let x represent the man's distance from building,
initially x = 1m2
dx/d t= -2.3 m/s
Also Let y represent shadow height
so we determine dy/dt when x is 4m from the building
form the image description of the problem, we see two-like triangles with the same base and height ratios
so
2 / (12-x) = y / 12
24 = y(12 - x )
y = 24 / (12-x)
dy/dt = 24/(12-x)² × dx/dt
Now at x = 4,
we substitute
dy/dt will be;
⇒ 24/(12 - 4)² × -2.3
= 24/64 - 2.3
= 0.375 × -2.3
dy/dt = - 0.8625 m/s
Therefore, the rate of the change of the length of the shadow is - 0.8625 m/s.
The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.
Answer:
(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C
Explanation:
(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J
The electric potential is given by
W = q V
(b)
charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m
Let the potential is V.
(c)
Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V
Let the charge is q.
W= q V
Answer:
<h2>The magnitude of the magnetic is 0.145 T</h2>Explanation:
Given :
Speed of proton
Mass of proton Kg
The force on the proton in magnetic field is given by,
But (∵ Force is perpendicular to the velocity so
)
When particle enter in magnetic field at the angle of 90° so particle moves in circle
So force is given by,
Where radius but in our case 0.23 m,
C
By comparing above two equation,
T