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3 years ago

7

Calculate the magnitude of the acceleration of Io due to the gravitational force exerted by Jupiter. [Show all work, including t

he equation and substitution with units.]
ag = Fg
m

1 answer:

galina1969 [7]3 years ago

4 0

The magnitude of the acceleration due to the gravitational force exerted by Jupiter is 25.91 m/s².

<h3>What is acceleration due to gravity?</h3>

This is the acceleration of a body under a free fall due to influence of gravity.

The magnitude of the acceleration due to the gravitational force exerted by Jupiter is calculated as follows;

$F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}$

where;

M is mass of Jupiter
R is the radius of Jupiter
G is universal constant

$g = \frac{6.67 \times 10^{-11} \times 1.8986 \times 10^{27}}{(69,911 \times 10^3)^2} \\\\g = 25.91 \ m/s^2$

Thus, the magnitude of the acceleration due to the gravitational force exerted by Jupiter is 25.91 m/s².

Learn more about acceleration due to gravity here: brainly.com/question/88039

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How does speed relate to motion energy?

Murljashka [212]

the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

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4 years ago

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The milky way galaxy is the galaxy that is closest to us contains the most stars is farthest from us contains our solar system

yKpoI14uk [10]

The Milky Way galaxy is the one that the sun is a member of, and it contains
our solar system. We're in it, and you can't get much closer than that.

The Milky Way is known to be bigger than your average galaxy, but it's
probably not correct to say that it contains the 'most' stars of any galaxy.
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3 years ago

Refer to the first diagram. What is the weight of the person hanging on the end of the seesaw in Newtons?

irina1246 [14]

Due to equilibrium of moments:

1) The weight of the person hanging on the left is 250 N

2) The 400 N person is 3 m from the fulcrum

3) The weight of the board is 200 N

Explanation:

1)

To solve the problem, we use the principle of equilibrium of moments.

In fact, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

The moment of a force is defined as:

$M=Fd$

where

F is the magnitude of the force

d is the perpendicular distance of the force from the fulcrum

In the first diagram:

- The clockwise moment is due to the person on the right is

$M_c = W_2 d_2$

where $W_2 = 500 N$ is the weight of the person and $d_2 = 2 m$ is its distance from the fulcrum

- The anticlockwise moment due to the person hanging on the left is

$M_a = W_1 d_1$

where $W_1$ is his weight and $d_1 = 4 m$ is the distance from the fulcrum

Since the seesaw is in equilibrium,

$M_c = M_a$

So we can find the weight of the person on the left:

$W_1 d_1 = W_2 d_2\\W_1 = \frac{W_2 d_2}{d_1}=\frac{(500)(2)}{4}=250 N$

2)

Again, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

- The clockwise moment due to the person on the right is

$M_c = W_2 d_2$

where $W_2 = 400 N$ is the weight of the person and $d_2$ is its distance from the fulcrum

- The anticlockwise moment due to the person on the left is

$M_a = W_1 d_1$

where $W_1 = 300 N$ is his weight and $d_1 = 4 m$ is the distance from the fulcrum.

Since the seesaw is in equilibrium,

$M_c = M_a$

So we can find the distance of the person on the right:

$W_1 d_1 = W_2 d_2\\d_2 = \frac{W_1 d_1}{W_2}=\frac{(300)(4)}{400}=3 m$

3)

As before, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

- The clockwise moment around the fulcrum this time is due to the weight of the seesaw:

$M_c = W_2 d_2$

where $W_2$ is the weight of the seesaw and $d_2 = 3 m$ is the distance of its centre of mass from the fulcrum

- The anticlockwise moment due to the person on the left is

$M_a = W_1 d_1$

where $W_1 = 600 N$ is his weight and $d_1 = 1 m$ is the distance from the fulcrum

Since the seesaw is in equilibrium,

$M_c = M_a$

So we can find the weight of the seesaw:

$W_1 d_1 = W_2 d_2\\W_2 =\frac{W_1 d_1}{d_2}= \frac{(600)(1)}{3}=200 N$

#LearnwithBrainly

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3 years ago

A 50.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and the

Dimas [21]

Answer:

98N and 147N

Explanation:

We have the following information:

$m=50kg\\\mu_s =0.4\\\mu_k = 0.2\\F=140N$

We can find the static fricton force as follow,

$F=\mu_s * N$

Where N is the normal force (mg)

$F=0.3*50*9.8\\F=147N$

Static friction force at 147N is greater than the force applied hence body does not move.

$F=\mu_k N = 0.2*50*9.8= 98N$

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4 years ago

Sound will travel slowest through which medium?

SSSSS [86.1K]

The speed of sound depends on the medium in which it is transported.

Sound travels fastest through solids, slower through liquids and slowest through gases.

So it will travel slowest through water at 55 degrees

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4 years ago

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