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hjlf
3 years ago
7

If the car has a mass of 0.4 kg, the ratio of height to width of the ramp is 19/85, the initial displacement is 1.9 m, and the c

hange in momentum is 1.27 kg*m/s, how far will it coast back up the ramp before changing directions (meters)?
Physics
1 answer:
Rasek [7]3 years ago
5 0

Answer:

final displacement lf  = 0.39 m

Explanation:

from change in momentum equation:

\delta p = m \sqrt(2g * y/x)* [\sqrt li + \sqrt lf]

given: m = 0.4kg, y/x = 19/85, li = 1.9 m,

\delta p = 1.27 kg*m/s.

putting all value to get the final displacement value

1.27 = 0.4\sqrt(2*9.81 *(19/85))* [\sqrt 1.9 + \sqrt lf]

final displacement lf  = 0.39 m

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Where would a car traveling on a roller coaster have the most kinetic energy ? and why?
goldenfox [79]

Answer:

As the car travels up the coaster it is gaining potential energy.

Explanation:

Because It has the greatest in amount of potential energy at the top of the coaster. when the car travels down the roller coaster it obtains speed and kinetic energy.

4 0
3 years ago
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An organ pipe of length 3.0 m has one end closed. The longest and next-longest possible wavelengths for standing waves inside th
iris [78.8K]

Answer:

The longest wavelength for closed at one end and open at the other is

y / 4      where y is the wavelength - that is node - antinode

The next possible wavelength is 3 y / 4 -    node - antinode - node -antinode

y / 4 = 3 m     y = 12 meters    the longest wavelength

3 y / 4 = 3 m      y = 4 meters   1 / 3 times as long

6 0
3 years ago
The critical angle for total internal reflection for cubic zirconia surrounded by air is 27.0°. Calculate the polarizing angle f
Anna11 [10]

Answer:

Polarizing angle, \theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}

Given:

Critical angle, \theta_{cr} = 27^{\circ}

Solution:

Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:

sin\theta_{cr} = \frac{1}{\mu_{Z}}                      (1)

where

{\mu_{Z} = refractive index of zirconia

From eqn (1):

\mu_{Z} = \frac{1}{sin\theta_{cr}}

\mu_{Z} = \frac{1}{sin(27^{\circ})} = 2.2

Now, the angle of polarization is given by:

tan\theta_{P} = \mu_{Z}

Therefore,

\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}

8 0
3 years ago
ASAP URGENT A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in
Umnica [9.8K]

Answer:

8018.2 N

Explanation:

Change in momentum, p is equivalent to force * time

M(vf-vi)=Ft where M represent mass of the car, vf is the final speed, vi is the intial speed of the car, F is the force in queation and t ia the time.

Since the car finally comes to rest then the final velocity ia zero. Substituting 1400 Kg for M, 0 for vf, 27 m/s for vi and 1.5 s for t then the first force is

1400(0-27)=1.5F

F=25200 N

Similarly, when we work with the same values but t changed to 2.2s

1400(0-27)=2.2 F

F2=17181.818181818 N

Reduced force will be 25200-17181.818181818=−8,018.181818182N

Approximately, 8018.2 N

3 0
3 years ago
Two resistors of 10 and 15 n are connected. What is their combined resistance if they are connected: a) in series b) in parallel
kati45 [8]

Explanation:

Given that,

Two resistors of 10 ohms and 15 ohms are connected.

In series combination, the equivalent resistance is given by :

R_s=R_1+R_2\\\\R_s=10+15\\\\R_s=25\ \Omega

In parallel combination, the equivalent resistance is given by :

\dfrac{1}{R_p}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_p}=\dfrac{1}{10}+\dfrac{1}{15}\\\\R_p=6\ \Omega

Hence, this is the required solution.

7 0
3 years ago
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