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mash [69]
3 years ago
9

A hydrocarbon is a compound that contains mostly carbon and hydrogen. Calculate the percent composition (by mass) of the followi

ng hydrocarbon: C5H12. Enter the percentages of carbon and hydrogen numerically to four significant figures, separated by commas. View Available Hint(s)
Chemistry
1 answer:
Shalnov [3]3 years ago
5 0

Answer: The percentages of carbon and hydrogen numerically to four significant figures is 83.33\% and 16.67\% respectively.

Explanation:

Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.

Mass of 1 mole of compound= mass of carbon + mass of hydrogen+ = 5(12) + 12(1)= 72 g.

a) Percentage by mass of carbon =\frac{\text {mass of carbon}}{\text {Total mass}}\times 100\ %

Percentage by mass of carbon =\frac{60}{72}\times 100\%=83.33\%

b) Percentage by mass of hydrogen =\frac{\text {mass of hydrogen}}{\text {Total mass}}\times 100\ %

Percentage by mass of hydrogen =\frac{12}{72}\times 100\%=16.67\%

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4) Non-metallic in nature

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g When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solut
Elden [556K]

Answer:

When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solution of sodium chloride. Write the conventional equation, total ionic equation, and net ionic equation for this reaction.

Explanation:

The word equation for the reaction is:

Copper (II) chloride(aq) + sodium carbonate (aq) ->sodium chloride (aq) +           copper carbonate(s)

The balanced chemical equation of the reaction is:

CuCl_2(aq)+Na_2CO_3(aq)->2NaCl(aq)+CuCO_3(s)

The complete ionic equation is:

Cu^2+(aq)+2Cl^-(aq)+2Na^+(aq)+CO_3^2^-(aq)->2Cl^-(aq)+2Na^+(aq)+CuCO_3(s)\\

The net ionic equation is obtained from the complete ionic equation after removing the spectator ions:

Cu^2^+(aq)+CO_3^2^-(aq)->CuCO_3(s)

5 0
3 years ago
8. When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. I
Julli [10]

Hey there!:

8) ΔTb = i*Kb*m  

 m is molality

 Since same number of mol is added to same amount of water in both cases

m will be same for both

is 1 for glucose since it is covalent compound

is 4 of Al(NO3)3 as it breaks into 1 Al₃⁺ and 3 NO₃⁻

So,  ΔTb will be 4 times in aluminum nitrate case

So, boiling point will change by 4ºC


9) use Q = m*  L

L =  heat of vaporization so:

T1=T2=100ºC

5.40 * 1000 => 5400  cal/g

Q =   5400 / 540

Q = 10 grams


Hope that thlps!

5 0
4 years ago
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