Assume 1mol of Al2O3:
mm(Al) = 26.98g/mol
x2(moles needed in 1mol of Al2O3)
= 53.96g
~54g
mm(O) = 16.00g/mol
x3(moles needed in 1mol of Al2O3)
=48g
mm(Al2O3) = m(Al) + m(O)
= 102g/mol
x1mol
=102g (in 1 mol)
<em>What</em><em> </em><em>percent</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>total</em><em> </em><em>does</em><em> </em><em>X</em><em> </em><em>or</em><em> </em><em>Y</em><em> </em><em>take</em><em> </em><em>up</em><em>?</em>
Just take the portion that it gets and divide by the total:
Al: 54/102 = 53%
O: 48/102 = 47% or 100%-53%=47%
<em>Notice that, with binary compounds, you only need to calculate one of the two elements: the remaining amount HAS to be taken up by the other element, or else there would be something else involved.</em>
Answer:
0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.
Explanation:
According to reaction, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide.
Then 1.8 moles of sulfuric acid will react with:
moles of NaOH.
Molarity of NaOH = 4.0 M
Moles of NaOH= n = 3.6 mol
Volume of NaOH = V
0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.
The answer to your questions is as follows:
most soluble
>CH3CH2OH
>CH3OCH3
>CH3CH3
<span>least soluble
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Answer: 0.86g/mL
Explanation:
Mass of empty cylinder = 23.731g
Mass of cylinder + liquid = 26.414g
Mass of the liquid = 26.414 — 23.731
= 2.683g
Volume of the liquid = 3.12mL
Density = Mass / volume
Density = 2.683g / 3.12mL
Density = 0.86g/mL
Answer:
Cs is cesium and CrO₄ is chromate so CsCrO₄ is cesium chromate.
