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Answer:
Indoles
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Answer:
Explanation: A compound with the empirical formula SO has a molecular weight of 96.13
Answer:
Ksp = 2.4 * 10^-13
Explanation:
Step 1: Data given
Molarity of NaIO3 = 0.10 M
The molar solubility of Pb(IO3)2 = 2.4 * 10^-11 mol/L
Step 2: The initial concentration
NaIO3 = 0.1M
Na+ = 0 M
2IO3- = 0 M
Step 3: The concentration at the equilibrium
All of the NaIO3 will react (0.1M)
At the equilibrium the concentration of NaIO3 = 0 M
The mol ratio is 1:1:1
The concentration of Na+ and IO3- is 0.1 M
Pb(IO3)2 → Pb^2+ + 2IO3^-
The concentration of Pb(IO3)2 can be written as X
The concentration of Pb^2+ can be written as X
The concentration of 2IO3^- can be written as 2X
Ksp = (Pb^2+)(IO3^-)²
⇒ with (Pb^2+) = 2.4*10^-11
⇒ with (IO3^-) = 2x from the Pb(IO3)2 and 0.1M from the NaIO3.
⇒The total (IO3^-) = 2x + 0.1 and we assume that x is so small that we can neglect it.
Ksp = (2.4 *10^-11)*(0.1)²
Ksp = 2.4 * 10^-13
The stratosphere. The lower boundary of the stratosphere is called the tropopause; the upper boundary is called the stratopause. Ozone<span>, an unusual type of oxygen molecule that is relatively abundant in the stratosphere, heats this layer as it absorbs energy from incoming ultraviolet radiation from the Sun.</span>
Answer: ratio is 10⁻⁵
Explanation:
From Acid-dissociation equilibrium constant, HA is given thus,
HA + H₂O ⇄ H₃O⁺ + A⁻
equilibrium constant, Ka = [H₃O⁺] [A⁻] / [HA]
[H₃O⁺] = Ka [HA] / [A⁻]
from this we have that
pH = -log[H₃O⁺]
and pKa = -logKa
Applying Henderson-Hassel bach equation;
pH = pKa + log [A⁻]/[HA] ...........(1)
A⁻ rep the salt and HA rep the acid
at a given pH of 7, the pKa value of carboxylic acid COOH is 3
∴ from equation (1).
7 = 3 + log(COO⁻/COOH)
log(COO⁻/COOH) = 4
thus (COO⁻/COOH) = 10⁻⁴ ...................(2)
The ratio of alanine COOH to COO- at pH 7 is (COO⁻/COOH) = 10⁻⁴
(ii) Also considering the ratio of alanine NH2 to NH3+ at pH 7 we have;
given Pka value is 8,
therefore pH = pKa + log [salt]/[base]
7 = 8 + log (NH₂/NH₃)
(NH₂/NH₃) = 10⁻¹
thus the ratio of the concentration of the neutral amino acid species to the zwitterionic species at pH 7 is;
10⁻⁴ ˣ 10⁻¹ = 10⁻⁵
cheers i hope this helps