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Nadya [2.5K]
3 years ago
9

How many cubic feet of air at standard conditions 1.00 atm are required to inflate a bicycle tote of .50 cu. Ft. To a pressure o

f 3.00 atmospheres?
Chemistry
1 answer:
Alexeev081 [22]3 years ago
3 0
As I am reading the problem, I see they gave you two pressures, one volume and they are asking for another volume. this should give you a hint that you need to use the following formula. 

P1V1= P2V2

P1= 1.00 atm
V1= 0.50 ft³
P2= 3.00 atm
V2= ?

Now we plug the values

(1.00 x 0.50)= (3.00 x V2)

V2= 0.17 ft³
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Catalytic converters made of palladium (pd) reduce automobile pollution by catalyzing the reaction between unburned hydrocarbons
Doss [256]
Unburned hydrocarbon on reacting with oxygen undergoes combustion reaction. However, the activation energy of this reaction is significantly high. When a catalyst like Pd is added to the reaction system, it provides active sites for the reaction to occur. It acts are a heterogeneous catalyst. It is pertinent of note that catalyst is refereed as heterogeneous, when it exist in different phase as compared to reactant and products. In present case, reactants and products are in gas phase, while catalyst is in solid phase. Due to availability of larger surface area at active site of Pd, activation energy of reaction decreases and decrease in activation energy favors higher reaction rates. 
3 0
3 years ago
Given similar concentrations, the stronger acid corresponds to the lower pH. Comment on the relative strengths of the acids H3PO
andreyandreev [35.5K]

Answer:

H3PO4 is stronger than H2PO4- because

H3PO4 dissociation constant is 6.9×10^-3

H2PO4^- dissociation constant is 6.2×10^-8

7 0
2 years ago
For the following reaction, 4.07 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 10.4 grams of
torisob [31]

Answer:

Theoretical yield = 13.7 g

% yield =76 %

Explanation:

For Al_2O_3

Mass of Al_2O_3  = 4.07 g

Molar mass of Al_2O_3  = 101.96 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{4.07\ g}{101.96\ g/mol}

Moles\ of\ Al_2O_3= 0.0399\ mol

According to the reaction:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

1 mole of Al_2O_3  on reaction produces 1 mole of Al_2(SO_4)_3

So,  

0.0399 mole of Al_2O_3  on reaction produces 0.0399 mole of Al_2(SO_4)_3

Moles of Al_2(SO_4)_3  obtained = 0.0399 mole

Molar mass of Al_2(SO_4)_3 = 342.2 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0399= \frac{Mass}{342.2\ g/mol}

Mass= 13.7\ g

<u>Theoretical yield = 13.7 g</u>

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100

Given , Values from the question:-

Theoretical yield = 13.7 g

Experimental yield = 10.4 g

Applying the values in the above expression as:-

\%\ yield =\frac{10.4}{13.7}\times 100

<u>% yield =76 %</u>

6 0
3 years ago
The pressure on 2.50 L of gas is changed from 4.5 atm to 2.2 atm. What is the new volume of gas?
swat32

Answer:

<h2>5.11 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{2.5 \times 4.5}{2.2}  =  \frac{11.25}{2.2}  \\  = 5.1136666...

We have the final answer as

<h3>5.11 L</h3>

Hope this helps you

8 0
3 years ago
Methane (CH4) burns in oxygen to produce carbon dioxide and water. Which reaction is occurring here?
Leto [7]
B..combustion is the answer
4 0
3 years ago
Read 2 more answers
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