Iron, or Fe, is the only element here. The rest are alloys. I hope this helps!
Answer:
The chemical term in the equation for the precipitate of AgCl(s) is n=3.54*10^-3
Explanation:
the quantity of AgCl(s) in moles is:
n = 0.508g / 143.32 g/mol = 3.54*10^-3 mol
to verify it the mass of AgNO3 involved in the reaction should be
n AgNO3 required = n = 3.54*10^-3 mol
the mass of n involved should be higher than n AgNO3
n existing = V*N = 0.523 mol/L * 35*10^-3 L = 18.305*10^-3 mol
The first one is the 2Hg+.....
The second is the Ca+ 2H2O....
The third is the first one, H2 + Cl2...
And the last is Fe+ S= FeS
It was so easy
Good Luck
Answer: remove a H2 molecule from the left side of the equation
Explanation:
