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Lunna [17]
3 years ago
14

A gold bar contains 5 moles of gold. How many atoms of gold are present in the bar?

Chemistry
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

= 3.01 x 10²³ atoms of gold (Au)

Explanation:

1 mole of any substance => 1 Avogadro's Number of particles = 6.02 x 10²³ particles.

∴ for 5 moles of gold atoms => 5 moles x 6.02 x 10²³ atoms/mole

= 3.01 x 10²³ atoms of gold (Au)

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The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
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Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

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Write down your own critique about the world is too much with us by William Wordsworth help ​
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