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laila [671]
3 years ago
8

If an element contains 8 electrons how many electrons will be placed in the 2nd valence shell?

Chemistry
2 answers:
blondinia [14]3 years ago
4 0

Explanation:

As it is given that the element contains a total of 8 electrons. So, electronic distribution of this element will be 2, 6.

That is, there will be two electrons present in first shell and there will be six electrons present in second valence shell.

Here, we also get to know that this element contains 6 valence electrons hence, it is a group 16 element.

Thus, we can conclude that if an element contains 8 electrons then 6 electrons will be placed in the 2nd valence shell.

RideAnS [48]3 years ago
3 0
If an element contains 8 electrons, then there would be 6 electrons that will be placed in the 2nd valence shell. Each shell in an atom can only take up a fixed number of electrons. For the first shell, only two electrons can be found. For the second shell, it can hold up to 8 electrons. However, for this case only six electrons can be found since the others are found in the first shell.
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Answer:

9.7 g

Explanation:

From the question,

Note: The molar volume of all gas at stp is 22.4 dm³ or 22.4 L

1 mol of  oxygen gas (O₂) at stp = 22.4 dm³

X mole of oxygen gas (O₂) at stp = 6.8 L

X = (1 mol×6.8 L)/22.4 L

X = 0.3036 mol.

But,

Number of mole (n) = mass (m)/molar mass (m')

n = m/m'

m = n×m'.................. Equation 2

Where n = 0.3036 mol, m' = 32 g/mol

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3 years ago
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