Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b
![r = \frac{ k [NO_2]^2 [F_2]}{[NO_2F]}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B%20k%20%5BNO_2%5D%5E2%20%5BF_2%5D%7D%7B%5BNO_2F%5D%7D)
Explanation:
From the question we are told that
The formation mechanism is
The overall balanced equation is
We combined the first reactant and the last product and the balanced the number of mole
The observable rate law is
This rate law is derived from the balanced chemical equation
Answer:
i fi am not wrong the correct answer is D
Explanation:
<span>Thyroid hormones T4, T3
</span><span>Cortisol
</span><span>Estrogen or testosterone
</span><span>Insulinlike growth factor-I (IGF-I)</span>
Answer:
Mass = 28.08
Explanation:
Given data:
Mass of Al₂O₃ = 21.8 g
Mass of water = 9.7 g
Mass of Al(OH)₃ = ?
Solution:
Chemical equation:
2Al(OH)₃ → Al₂O₃ + 3H₂O
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 9.7 g/ 18 g/mol
Number of moles = 0.54 mol
Number of moles of Al₂O₃:
Number of moles = mass/molar mass
Number of moles = 21.8 g/ 101.96 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of Al(OH)₃ with Al₂O₃ and H₂O.
Al₂O₃ : Al(OH)₃
1 : 2
0.21 : 2×0.21 = 0.42 mol
H₂O : Al(OH)₃
3 ; 2
0.54 : 2/3×0.54 = 0.36 mol
Mass of Al(OH)₃:
Mass = number of moles × molar mass
Mass = 0.36 mol × 78 g/mol
Mass = 28.08 g
<span>Number of moles of Fe(CO)5 = mass/molar mass = (6.0 g) / (195.8955 g/mol) = 0.03 mol
Number of moles of PF3 = (4.0 g)/ (87.97 g/mol) = 0.0455 mol
Number of moles of H2 = (4.0 g) / (2.016 g/mol) = 1.984 mol
From the balanced equation
1 mol of Fe(CO)5 reacts with 2 mol of PF3 and 1 mol of H2
then 0.03 mol of Fe(CO)5 will need 0.03 (2/1) = 0.06 mol of PF3 and 0.03 mol of H2
Since we have less PF3 ( 0.0455 mol instead of 0.06 mol), that is the limiting agent</span>
