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ohaa [14]
3 years ago
11

What do you predict would happen if you conducted this experiment using sulfur hexafluoride (sf6) which is much heavier than met

hane or butane?
Chemistry
1 answer:
Sophie [7]3 years ago
4 0

The volume of SF6 would be larger and this would affect the pressure in the flask .

Explanation:

If we conducted an experiment using same number of moles of sulfur hexafluoride (SF6) ,methane or butane, there will be no any effect on temperature, pressure  and volume. But if we conducted an experiment using same weight of sulfur hexafluoride, methane or butane, there will be some effect on temperature, pressure and volume.

Hope that helps!

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How many moles are in 29.5 grams of Ax?
JulsSmile [24]

The number of moles present in 29.5 grams of argon is 0.74 mole.

The atomic mass of argon is given as;

Ar = 39.95 g/mole

The number of moles present in 29.5 grams of argon is calculated as follows;

39.95 g ------------------------------- 1 mole

29.5 g ------------------------------ ?

= \frac{29.5}{39.95} \\\\= 0.74 \ mole

Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.

<em>"Your question seems to be missing the correct symbol for the element" </em>

Argon = Ar

Learn more here:brainly.com/question/4628363

6 0
3 years ago
In a two-step synthesis, C6H11Br is converted into C6H12O. From the structure of the product, molecular formula of the starting
tamaranim1 [39]

Answer:

See explanation below

Explanation:

The question is incomplete. However in picture 1, you have the starting materials and the structure of the product, which you miss in this part.

Now, in picture 2, you have the starting reactant and the product, and the mechanism that is taking place here.

First, all what we have here is an acid  base reaction. In the first step, we are using the acid medium to convert the reactant into an alcohol. The bromine there, is not leaving the molecule yet, because it's neccesary for the next step. The starting reactant is an alkene, in that way, we can convert the reactant in the first step into a secondary alcohol. In other words, the first reaction is a alkene hydration.

In the second step, we use a strong base. You may say this is a strong nucleophile and will do a Sn2 reaction to form another alcohol there, but it's not the case, because, before any kind of reaction happens, the priority here is always the acid base, so the base will react with the acidic hydrogen. In this case, it will substract an hydrogen from the OH. When this happens, the lone pair will do an auto condensation here, and attacks the bromine in the molecule. In this way, the molecule will become a cyclomolecule, and that way it form the final product.

See picture 2, for mechanism

8 0
3 years ago
Write the balanced chemical equation for the following: The destruction of a marble statuary by acid rain: aqueous nitric acid r
Mashcka [7]

Answer: The coefficient in front of nitric acid is 2

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas. Liquids are represented by (l) and gases are represented by (g).

The balanced chemical reaction is :

CaCO_3(s)+2HNO_3(aq)\rightarrow Ca(NO_3)_2(aq)+CO_2(g)+H_2O(l)

7 0
3 years ago
2. If 1.75 L of a gas is at 700. K and is under 250. kPa of pressure, what will the new
Andrews [41]

Answer:

Final volume is 3.50L

Explanation:

It is possible to find volume of a gas using combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

<em>Where P is pressure, V is volume and T is temperature of 1: initial state and 2: final state</em>

If initial state of the gas is:

1.75L of a gas is at 700K and is under 250kPa of pressure

And final state is:

298K and 53.2kPa.

Replacing:

\frac{250kPa*1.75L}{700K} =\frac{53.2kPa*V_2}{298K}

0.625L = 0.1785*V₂

<em>3.50L = V₂</em>

Thus, <em>final volume is 3.50L</em>

3 0
3 years ago
CaC12 + NaCO3–&gt;CaCO3 +NaC1
lapo4ka [179]
I think it would be c
7 0
3 years ago
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