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ohaa [14]
3 years ago
11

What do you predict would happen if you conducted this experiment using sulfur hexafluoride (sf6) which is much heavier than met

hane or butane?
Chemistry
1 answer:
Sophie [7]3 years ago
4 0

The volume of SF6 would be larger and this would affect the pressure in the flask .

Explanation:

If we conducted an experiment using same number of moles of sulfur hexafluoride (SF6) ,methane or butane, there will be no any effect on temperature, pressure  and volume. But if we conducted an experiment using same weight of sulfur hexafluoride, methane or butane, there will be some effect on temperature, pressure and volume.

Hope that helps!

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Which type of bonding is most important in ch3ch2ch2ch2ch2ch3?
saveliy_v [14]

The compound CH_3CH_2CH_2CH_2CH_2CH_3 is formed only by sharing of electrons between the atoms. The structure of the compound is shown in the image.

Each line between two atoms represents the sharing of an electron pair which results in the formation of a single bond. Since, carbon has 4 electrons in its valence shell and hydrogen has 1 electron in its valence shell so in order to complete the octet ( to have 8 electrons in their valence shell, noble gas configuration) to attain stability carbon needs 4 more electrons and hydrogen needs 1 electron. So, sharing of electron will occur as shown in the image and the formed compound is stable in nature.

Since, the bond that is formed by sharing of electrons between atoms is known as covalent bond. So, covalent bonding is most important in CH_3CH_2CH_2CH_2CH_2CH_3.

7 0
3 years ago
The liter is used to measure _____.<br><br> weight<br> mass<br> volume<br> length
Ket [755]

the answer to your question is

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4 0
3 years ago
Read 2 more answers
A sample of a hydrocarbon is found to contain 7.48g carbon and 2.52g hydrogen. What is the empirical
Aliun [14]

Answer:

CH₄

Explanation:

To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.

Step 1: Determine the mass of the compound

The mass of the compound is equal to the sum of the masses of the elements that form it.

m(CxHy) = mC + mH = 7.48 g + 2.52 g = 10.00 g

Step 2: Calculate the percent by mass of each element

%C = mC / mCxHy × 100% = 7.48 g / 10.00 g × 100% = 74.8%

%H = mH / mCxHy × 100% = 2.52 g / 10.00 g × 100% = 25.2%

Step 3: Divide each percentage by the atomic mass of the element

C: 74.8/12.01 = 6.23

H: 25.2/1.01 = 24.95

Step 4: Divide both numbers by the smallest one, i.e. 6.23

C: 6.23/6.23 = 1

H: 24.95/6.23 ≈ 4

The empirical formula of the hydrocarbon is CH₄.

6 0
3 years ago
Convert 25 mg to unit HG
Degger [83]
Your answer would be 250,000
6 0
3 years ago
Which element has properties most similar to those of chromium
Vedmedyk [2.9K]
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7 0
3 years ago
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