Answer:
140 K
Explanation:
Step 1: Given data
- Initial pressure of the gas (P₁): 3 atm
- Initial temperature of the gas (T₁): 280 K
- Final pressure of the gas (P₂): 1.5 atm
- Final temperature of the gas (T₂): ?
Step 2: Calculate the final temperature of the gas
We have a gas whose pressure is reduced. If we assume an ideal behavior, we can calculate the final temperature of the gas using Gay-Lussac's law.
T₁/P₁ = T₂/P₂
T₂ = T₁ × P₂/P₁
T₂ = 280 K × 1.5 atm/3 atm = 140 K
Explanation :
As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.

where,
is the amount of component 1 and 2 in the system.
Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable
are kept constant are known as partial molar Gibbs free energy of
component.
For a substance in a mixture, the chemical potential
is defined as the partial molar Gibbs free energy.
The expression will be:

where,
T = temperature
P = pressure
is the amount of component 'i' and 'j' in the system.
It has to be 120g because each and every chemical equation has to satisfy the law of conservation of mass, ie sum of mass of products is always equal to the sum of masses of reactants. If reactants=120g, then products=120g
it is water energy :) this is easy
Answer:
C
Explanation:
C because there is more in it than the rest of the idems