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nirvana33 [79]
3 years ago
7

You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y

ou purify a sample of 2 grams. One of your colleagues steals half of it, and six days later you find that 0.2 gram of the radioactive material is still left. What is the half-life
Chemistry
1 answer:
lbvjy [14]3 years ago
3 0

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

k=\frac{2.303}{6}\log\frac{1.0}{0.2}

k=0.268days^{-1}

b) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days

The half life is 2.58 days

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Answer:

[Ag^{+}]=4.2\times 10^{-2}M

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

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Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]

[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}

Now,

Ag_{2}CrO_4(s) \leftrightharpoons  2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}

[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M

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7 0
3 years ago
Which of the following are characteristics of vertebrates?
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<span><u><em>Answer:</em></u>
All of the above

<u><em>Explanation:</em></u>
Vertebrates are a class of creatures falling under kingdom "<u>Animalia</u>" that are characterized by the presence of an internal skeleton composed of bones.

<u>Vertebrates are characterized by the following:</u>
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Comparing the mentioned characteristics with the options given, we will find that the most suitable answer is: <u>"all of the above"</u>.

Hope this helps :)</span>
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