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Mice21 [21]
2 years ago
10

ithium metal reacts with water to give lithium hydroxide and hydrogen gas. if 75.5 mL of hydrogen gas is produce at STP, what is

the mass of lithium metal that reacted?
Chemistry
2 answers:
netineya [11]2 years ago
7 0
The reaction would written as:

2Li + 2H2O = 2LiOH + H2

We are given the amount in volume of the hydrogen gas that is produced. Assuming that this gas is an ideal gas, we use the relation that in every 1 mol of gas, 22.4 L is being occupied.

75.5 mL ( 1 L / 1000 mL ) ( 1 mol / 22.4 L ) = 0.0034 mol H2 produced

0.0034 mol H2 ( 2 mol Li / 1 mol H2 ) ( 6.941 g / mol ) = 0.0472 g Li is needed
Galina-37 [17]2 years ago
6 0
The reaction equation may be written as:
2Li + 2H₂O → 2LiOH + H₂

A single mole of gas occupies 22,400 ml of gas at STP. Therefore, the moles of hydrogen gas are
75.5 / 22,400 = 0.0034 mol
According to the equation, the moles of lithium are twice that of hydrogen gas; thus,
0.0034 x 2 = 0.0068 mol

The mass of lithium is given by:
mass = moles x atomic mass
mass = 0.0068 x 6.9
mass = 0.047 grams
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Melted rock and minerals below the earth's crust is also known as magma
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What are the main reactants and products in a neutralization reaction?
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The reactants in the neutralization reaction are an acid and a base while the products are a salt and water.

7 0
3 years ago
8. What volume (ml) of a 5.45 M lead nitrate solution must be diluted to 820.7 ml to make a
Ganezh [65]

212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.

Answer:

Option A.

Explanation:

Similar to Avagadro's law, there is another law termed as dilution law. As the product of volume and normality of the reactant is equal to the product of volume and normality of the product from the Avagadro's law. In dilution law, it will be as product of volume and concentration of the solute of the reactant is equal to the product of volume and concentration of solution.

C_{1} V_{1} =C_{2} V_{2}

So, as per the given question C1 = 5.45 M of lead nitrate and V1 has to be found. While C2 is 1.41 M of lead nitrate and V2 is 820.7 ml.

Then, (5.45*V_{1} ) = (820.7*1.41)

V_{1}=\frac{820.7*1.41}{5.45}=  212.33 ml

So nearly 212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.

3 0
2 years ago
Why doesn't glue stick to the inside of the bottle? (Not sure if this is chemistry or not lol)
Leni [432]

Answer:

When white glue is in the bottle, there's not enough air inside the bottle to cause the water to evaporate to make the glue sticky. Basically, the bottle holds the glue from the air and keeps the glue from going everywhere.

8 0
2 years ago
For the reaction C2H4(g) + H2O(g) --> CH3CH2OH(g)
Dominik [7]

Answer : The value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = -45.6 kJ = -45600 J

\Delta S^o = standard entropy = -125.7 J/K

T = temperature of reaction = 262.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(-45600J)-(262.0K\times -125.7J/K)

\Delta G^o=-12666.6J=-12.7kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = -12666.6 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 262.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

-12666.6J=-(8.314J/K.mol)\times (262.0K)\times \ln k

k=3.35\times 10^{2}

Therefore, the value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

3 0
3 years ago
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