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sergey [27]
3 years ago
10

A + B-2C, ΔΗ1 1/2A + 1/5B+ C, ΔΗ» =?

Chemistry
1 answer:
weeeeeb [17]3 years ago
5 0

Answer:

2c

Explanation:

it just is

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Identify which one is the reducing agent in this reaction
Romashka-Z-Leto [24]

Answer:

Na.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
  • An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.
  • A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.

  • For the reaction:

<em>2Na + S → Na₂S.</em>

<em></em>

Na is oxidized to Na⁺ in (Na₂S) (loses 1 electron). "reducing agent".

S is reduced to S²⁻ in (Na₂S) (gains 2 electrons). "oxidizing agent".

6 0
3 years ago
Please help<br> Will give brainliest<br> A - 1<br> B - 2<br> C - 3<br> D - 4<br> E - 5
Basile [38]

Answer:

B-2

Explanation:

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4 0
2 years ago
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Explain the law of conservation of energy. Give a specific example using kinetic and potential energy that shows how energy is c
stira [4]

Answer:

Law of conservation of energy states that energy can neither be created nor can be destroyed but can be changed from one form to another

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8 0
3 years ago
If 73.5 mL of 0.200 M KI(aq) was required to precipitate all of the lead(II) ion from an aqueous solution of lead(II) nitrate, h
frutty [35]

Answer:

There were 0.00735 moles Pb^2+ in the solution

Explanation:

Step 1: Data given

Volume of the KI solution = 73.5 mL = 0.0735 L

Molarity of the KI solution = 0.200 M

Step 2: The balanced equation

2KI + Pb2+ → PbI2 + 2K+

Step 3: Calculate moles KI

moles = Molarity * volume

moles KI = 0.200M * 0.0735L = 0.0147 moles KI

Ste p 4: Calculate moles Pb^2+

For 2 moles KI we need 1 mol Pb^2+ to produce 1 mol PbI2 and 2 moles K+

For 0.0147 moles KI we need 0.0147 / 2 = 0.00735 moles Pb^2+

There were 0.00735 moles Pb^2+ in the solution

3 0
3 years ago
Amalgam is an alloy that contains mercury and other metals. Which of these atoms would most likely form metallic bonds with merc
rusak2 [61]
I would say copper, silver, and tin, since an alloy is a mixture of metals and metalloids.
6 0
3 years ago
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