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sergey [27]
4 years ago
10

A + B-2C, ΔΗ1 1/2A + 1/5B+ C, ΔΗ» =?

Chemistry
1 answer:
weeeeeb [17]4 years ago
5 0

Answer:

2c

Explanation:

it just is

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10.0 grams of water are heated during the preparation of a cup of coffee 1.0x 103 j of the heat are added to the water. which is
katovenus [111]

<u>Answer:</u> The final temperature of the coffee is 43.9°C

<u>Explanation:</u>

To calculate the final temperature, we use the equation:

q=mC(T_2-T_1)

where,

q = heat released = 1.0\times 10^3J=1000J

m = mass of water = 10.0 grams

C = specific heat capacity of water = 4.184 J/g°C

T_2 = final temperature = ?

T_1 = initial temperature = 20°C

Putting values in above equation, we get:

1000J=10.0g\times 4.184J/g^oC\times (T_2-20)\\\\T_2=43.9^oC

Hence, the final temperature of the coffee is 43.9°C

6 0
4 years ago
An earthquake’s magnitude is a measure of the
marissa [1.9K]
An earthquake's magnitude is a measure of how much energy an earthquake releases. Typically, the richter scale is used.
8 0
3 years ago
Read 2 more answers
Is it possible to make new water
alexandr1967 [171]

No, Matter cannot be created nor deastroyed.

5 0
3 years ago
Read 2 more answers
Please help me
Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

8 0
3 years ago
What is the ph of a 0.014 M HCL solution?
Allushta [10]

Answer:

pH = 1.853

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

[H_3O^+] = [HCl] = 0.014

pH  = -log [H^+] = -log [H_3O^+]

Substituting the available values in above equation, we can say that   the pH of the solution is equal to

- log (0.014)

pH = 1.853

pH of a 0.014 M HCL solution = 1.853

8 0
3 years ago
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