Answer:
75 m
Explanation:
The distance x for a uniform acceleration is given by the equation:
The given values are:
a = 6 m/s², t = 5 s, v₀ = 0, x₀ = 0
When landing after a spectacular somersault, a 45.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the fo
1 answer:
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Explanation:
It is given that,
Speed of the baseball, u = 44 m/s
Speed of the baseball, v = 53 m/s
Mass of the ball, m = 145 g = 0.145 kg
Time of contact between the ball and the bat, t = 2.2 ms = 0.0022 s
F₁ = 2900 N...........(1)
F₂ = 3493.18 N.........(2)
In average vector form force is given by :
Hence, this is the required solution.
Explanation:
Given that, the height of the tide measured at a seaside community varies according to the number of hours t after midnight. The height is given by the equation as :
When the tide first be at 6 ft, put h = 6 ft in above equation as :
On solving the above equation to find the value of t. It is equal to :
t = 3.551 seconds
or
t = 8.449 seconds
So, the tide of 6 ft is at 3.551 seconds and 8.449 seconds. Hence, this is the required solution.