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kompoz [17]
3 years ago
6

When landing after a spectacular somersault, a 45.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the fo

rce she must exert if her deceleration is 8.00 times the acceleration of gravity.?
Physics
1 answer:
STALIN [3.7K]3 years ago
6 0
So the force that the gymnast with a mass m=45 kg, has to exert against the ground to stop if her acceleration is a=8*g, where g=9.81 m/s², can be obtained from the Newtons second law: F=m*a, where F is the force, m is the mass and a is acceleration. 

F=m*a=m*8*g=45*8*9.81=3531.6 N. 

So the force that a gymnast has to exert on the mat in order to stop is F=3531.6 N.  
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From the movement of sunspots, Galileo discovered that sun rotate s on its own axis.

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-17.5 nC

Explanation:

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The radius of Earth is . The average Earth-Sun distance is . How many Earths would fit between Earth and the Sun if they are sep
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Consider two massless springs connected in series. Spring 1 has a spring constant k1, and spring 2 has a spring constant k2. A c
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Answer:

a. k = (1/k₁ + 1/k₂)⁻¹ b. k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

Explanation:

Since only one force F acts, the force on spring with spring constant k₁ is F = k₁x₁ where x₁ is its extension

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B

The force on spring with spring constant k₃ is F = k₃x₃ where x₃ is its extension

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x = F/k = F/k₁ + F/k₂ + F/k₃

1/k = 1/k₁ + 1/k₂ + 1/k₃

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