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sergij07 [2.7K]
4 years ago
5

You are leaving for a party at your cousin’s house in a city that is 150 km away. You will travel at an average rate of 50 km/hr

. How long will it take you to arrive?
Physics
2 answers:
Kamila [148]4 years ago
6 0

Answer : It take time to arrive will be 3 hours.

Explanation :

Average rate : It is defined as the ratio total distance to total time.

Formula used :

\text{Average rate}=\frac{\text{Total distance}}{\text{Total time}}

As per question,

Total distance traveled = 150 km

Average rate = 50 km/hr

Now put all the given values in the above formula, we get:

\text{Average rate}=\frac{\text{Total distance}}{\text{Total time}}

50km/hr=\frac{150km}{\text{Total time}}

\text{Total time}=\frac{150km}{50km/hr}=3hr

Therefore, it take time to arrive will be 3 hours.

choli [55]4 years ago
5 0
3 hours, because for every 50 km equals one hour 150 divided into 50 equals 3
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Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure. The radii of their orbits ar
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By 272.7 degrees angle has planet Y rotated through during this time.

<h3 /><h3>What is Kepler's 3rd law?</h3>

The cubes of the semi-major axes of the planets' orbits are precisely proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius rises, so does the time of its orbit around the Sun.

Using Kepler's 3rd law, which says that the period of any planet's orbit squared is proportional to the radius of the orbit cubes, we can establish that

(period X / period Y)^2 = (radius X / radius Y)^3

(period X / period Y)^2 = 2^3 = 8

take sq root

period X / period Y = √8 = 2.82≅ 3

this means it takes planet X 2.82≅ 3  times longer to go through one orbit... so planet Y travels 2.82≅ 3  times as far (in its orbit...) as planet X!

This means...

planet Y travels   3 * 90.9  =   272.7 degrees

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2 years ago
A rigid container holds 2.40 mol of gas at a pressure of 2.00 atm and a temperature of 40.0 ∘c. part a what is the container's v
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Almost 30.0 dm cubed
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3 years ago
A construction worker moved a crate full of equipment 15,0 m using a constant force
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Considering the definition of work and power, 157.5 W of power was developed.  

<h3>Power</h3>

Power is defined as how fast work is done. That is, power is the amount of work done per unit of time:

Power=\frac{work}{time}

P is the power developed by the force that performs the work and its unit of measurement in the International System is Watts (W).

The unit of measurement of work in the International System is the Joule (J). The time during which the work is developed has the unit of measurement in the International System of seconds (s).

<h3>Work </h3>

On the other side, work is defined as the force that is applied on a body to move it from one point to another.  

When a net force is applied to the body or a system and this produces displacement, then that force is said to perform mechanical work. This work can be positive if the system gains energy or negative if the system loses energy.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves.

<h3>This case </h3>

In this case, the angle between the force and the displacement is 0 degrees. This is because the force and the displacement are in the same direction and sense, in the horizontal direction. So the cosine of 0 degrees will have a value of 1. Then work is equal to:

Work= force× distance

Being the force 105 N and the distance 15 meters, the work can be calculated as:

Work= 105 N× 15 meters

Solving:

<u><em>Work=  1,575 J</em></u>

Finally, being the time 10 seconds, the power can be calculated as:

Power=\frac{1,575 J}{10 s}

Solving:

Power= 157.5 W

In summary, 157.5 W of power was developed.  

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2 years ago
Usually, large amount of curent flows in a<br> Circuit due to two reasons ———— and ————.
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Answer:

Explanation:

Possible causes for overcurrent include short circuits, excessive load, incorrect design, an arc fault, or a ground fault. Fuses, circuit breakers, and current limiters are commonly used overcurrent protection (OCP) mechanisms to control the risks

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8 0
3 years ago
7. A force stretches a wire by 1 mm. a. A second wire of the same material has the same cross section and twice the length. How
Lera25 [3.4K]

Answer:

(a) The second wire will be stretched by 2 mm

(b) The third wire will be stretched by 0.25 mm

Explanation:

Tensile stress on every engineering material is given as the ratio of applied force to unit area of the material.

σ = F / A

Tensile strain on every engineering material is given as the ratio of extension of the material to the original length

δ = e / L

The ratio of tensile stress to tensile strain is known as Young's modulus of the material.

Y = \frac{FL}{Ae}

<u></u>

<u>Part A</u>

cross sectional area and applied force are the same as the original but the length is doubled

\frac{FL_1}{A_1e_1} =  \frac{FL_o}{A_oe_o} \\\\\frac{L_1}{e_1} =  \frac{L_o}{e_o}\\\\e_1 = \frac{L_1e_o}{L_o} \\\\But, L_1 =2L_o\\\\e_1 = \frac{2L_oe_o}{L_o}\\e_1 = 2e_o

The second wire will be stretched by 2 mm

<u>Part B</u>

a third wire with the same length but twice the diameter of the first

\frac{FL}{A_1e_1} = \frac{FL}{A_oe_o} \\\\\frac{1}{A_1e_1} = \frac{1}{A_oe_o}\\\\\frac{4}{\pi d_1^2e_1} = \frac{4}{\pi d^2_oe_o}\\\\\frac{1}{d_1^2e_1} = \frac{1}{d^2_oe_o}\\\\d_1^2e_1 = d^2_oe_o\\\\e_1 = \frac{d^2_oe_o}{d_1^2} \\\\e_1 =(\frac{d_o}{d_1})^2e_o\\\\But, d_1 = 2d_o\\\\e_1 =(\frac{d_o}{2d_o})^2e_o\\\\e_1 =(\frac{1}{2})^2e_o\\\\e_1 =(\frac{1}{4})e_o

e₁ = ¹/₄ x 1 mm = 0.25 mm

The third wire will be stretched by 0.25 mm

3 0
4 years ago
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