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german
2 years ago
8

Two blocks of masses 1.0 kg and 2.0 kg, respectively, are pushed by a constant applied force F across a horizontal frictionless

table with constant acceleration such that the blocks remain in contact with each other, as shown above. The 1.0 kg block pushes the 2.0 kg block with a force of 2.0 N. The acceleration of the two blocks is
0

1.0 m/s2

1.5 m/s2

2.0 m/s2

3.0 m/s2
Physics
1 answer:
BaLLatris [955]2 years ago
6 0

Answer:

1.0 m/s^2

Explanation: happy to help :)

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Hooke’s law states that the distance that a spring is stretched by hanging object varies directly as the mass of the object. If
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Answer:

d_{2} = 33.33 cm

Explanation:

Given:

When mass, m_{1} =21 kg

          distance travelled is  d_{1}  = 140 cm

When mass, m_{2} =5 kg

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Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.

Therefore according to the question,

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\frac{140}{21}=\frac{d_{2}}{5}

d_{2} = 33.33 cm

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