Two blocks of masses 1.0 kg and 2.0 kg, respectively, are pushed by a constant applied force F across a horizontal frictionless
1 answer:
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Answer:
t = 4.28 s
Explanation:
The horizontal speed of a marble = 7 m/s
The horizontal displacement covered by the marble = 30 m
We need to find the time for which the marble is in air. Let the time is t. Using the formula for speed to find it as follows :
So, it will in the air for 4.28 s.
Answer: 1.12 m
Explanation:
This situation is related to parabolic motion, hence we can use the following equations:
(1)
(2)
Where:
is the ball final height (when it hits the ground)
is the ball initial height
is the initial velocity
is the angle at which the ball was launched
is the time
is the acceleration due gravity
is the horizontal distance the ball travels
Rewriting (1) with the given values:
(3)
Multiplying all the eqquation by -1 and rearranging:
(4)
So, since we have a quadratic equation here (in the form of, we will use the quadratic formula to find
:
(5)
Where ,
,
Substituting the known values and choosing the positive result of the equation, we have:
(6)
Now, substituting (6) in (2):
(7)
(8) This is the horizontal distance at which the ball hits the ground.