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Oksi-84 [34.3K]
3 years ago
14

PLEASE HELP!! PHYSICS QUESTION-DOES ANYONE KNOW HOW TO DO THIS WITH THE WORKING OUT?!?

Physics
1 answer:
notsponge [240]3 years ago
4 0

Answer:

1.5 \Omega

Explanation:

The resistance of a piece of wire is given by

R=\frac{\rho L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area

In this problem, we have

\rho = 3.3\cdot 10^{7} m

L = 7.0 m

The diameter of the wire is 0.14 cm, so the radius is 0.07 cm, therefore the cross sectional area is

A=\pi r^2 = \pi (0.07)^2=0.0154 cm^2 = 0.0154\cdot 10^{-4} m^2

Therefore, the resistance is

R=\frac{(3.3\cdot 10^{-7})(7.0)}{(0.0154\cdot 10^{-4})}=1.5 \Omega

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Who discovered the laws of physics
astra-53 [7]

Answer: Isaac Newton

Explanation: Isaac Newton is popularly remembered as the man who saw an apple fall from a tree, and was inspired to invent the theory of gravity. If you have grappled with elementary physics then you know that he invented calculus and the three laws of motion upon which all of mechanics is based.

6 0
3 years ago
I need to know how long the friend will drive before he meets me and how many miles I will have traveled by the time I meet him,
IceJOKER [234]
Let you be at point A while your friend be at point B,
while you are still having lunch,
you friend travels= 27/60*75miles/h=33.75miles
Remaining Distance= 135miles-33.75miles=101.25miles
Take note here is the tricky part, for the remaining distance both you and your friend are driving towards each other,
So first,
Total speed =Adding both ur friend and ur speed= 60+75=135miles/h
Time taken to meet= 101.25miles/135miles/h=0.75h
Total hours ur friend drives= 0.75h+27/60h=1.2h
total distance ur friend drove= 1.2h * 75miles/h= 90km
for the part how far u travelled,
simply take 135miles -90miles=45miles
4 0
3 years ago
Someone help me w my homework pls I need help 30 points ​
torisob [31]
I dont see a question 38 for the second one
6 0
3 years ago
What are northern lights? a lights on mars b lights on the sun c lights on venus
laiz [17]

The northern lights are shafts or curtains of colorful light that occasionally appear in the night sky. They are one of the numerous astronomical phenomena known as polar lights (aurora Polaris).This phenomenon may be observed in mars.

Earth's magnetic field directs electrons and protons from the sun to the poles, where they excite atmospheric gas molecules and cause them to glow, resulting in the aurora borealis and aurora australis, two nocturnal light displays. You might refer to it as the aurora Universalis on Mars. This is because Mars does not direct the energetic particles from the sun to its poles since it lacks an internal magnetic field. Today, researchers utilizing the MAVEN (Mars Atmosphere and Volatile Evolution) spacecraft find evidence for an aurora that may potentially cover the whole nightside of the planet. Venus lacks a magnetic field, thus it would not experience the same kind of nighttime aurora that we do.

To know more about aurora borealis go here:-

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8 0
2 years ago
Consider an ideal gas of 7 moles that is in contact with a thermal reservoir of temperature 475 K. The gas is enclosed in a cont
kozerog [31]

Answer:

(a). The initial pressure is 5.5\times10^{4}\ Pa

(b). The final pressure is 1.8\times10^{4}\ Pa

Explanation:

Given that,

Number of moles = 7

Temperature = 475 K

Initial volume = 0.50 m³

Expanded volume = 1.50 m³

We need to calculate the initial pressure

Using formula of pressure

P_{i}=\dfrac{nRT_{i}}{V_{i}}

Put the value into the formula

P_{i}=\dfrac{7\times8.31\times475}{0.50}

P_{i}=55261.5\ Pa

P_{i}=5.5\times10^{4}\ Pa

We need to calculate the final pressure

Using formula of pressure

P_{f}V_{f}=nRT_{f}

After expansion,

\dfrac{P_{f}V_{f}}{P_{i}V_{i}}=\dfrac{nRT_{f}}{nRT_{i}}

P_{f}=\dfrac{T_{f}}{T_{i}}\times\dfrac{P_{i}V_{i}}{V_{f}}

Put the value into the formula

For thermal process,

T_{i}=T_{f}

P_{f}=\dfrac{5.5\times10^{4}\times0.50}{1.50}

P_{f}=18333.33\ Pa

P_{f}=1.8\times10^{4}\ Pa

Hence, (a). The initial pressure is 5.5\times10^{4}\ Pa

(b). The final pressure is 1.8\times10^{4}\ Pa

3 0
4 years ago
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