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Liula [17]
3 years ago
12

If the speed of a wave doubles while the frequency remains the same, it means

Physics
1 answer:
sattari [20]3 years ago
5 0

Answer:

Explanation:

Velocity of a wave is describe as

velocity =Frequency × Wavelength

Mathematically

v = fλ

Hence, Frequency, F = v / λ

Wavelength λ = v/f

So, if the frequency is kept constant, wavelength of the wave becomes directly proportional to velocity of the wave.

And this implies that, as the speed double, the wavelength is double.

You might be interested in
A 12.0-g bullet is fired horizontally into a 104-g wooden block that is initially at rest on a frictionless horizontal surface a
kobusy [5.1K]

Answer:

 v₀ = 292.3 m / s

Explanation:

Let's analyze the situation, on the one hand we have the shock between the bullet and the block that we can work with at the moment and another part where the assembly (bullet + block) compresses a spring, which we can work with mechanical energy, as the data they give us are Let's start with this second part.

We write the mechanical energy when the shock has passed the bodies

    Em₀ = K = ½ (m + M) v²

We write the mechanical energy when the spring is in maximum compression

    Em_{f} = K_{e} = ½ k x²

    Em₀ = Em_{f}

    ½ (m + M) v² = ½ k x²

Let's calculate the system speed

    v = √ [k x² / (m + M)]

    v = √[154 0.83² / (0.012 +0.104) ]

    v = 30.24 m / s

This is the speed of the bullet + Block system

Now let's use the moment to solve the shock

Before the crash

    p₀ = m v₀

After the crash

   p_{f} = (m + M) v

The system is formed by the bullet and block assembly, so the forces during the crash are internal and the moment is preserved

   p₀ =  p_{f}

   m v₀ = (m + M) v

   v₀ = v (m + M) / m

let's calculate

   v₀ = 30.24 (0.012 +0.104) /0.012

   v₀ = 292.3 m / s

3 0
3 years ago
1. Identify the significance of the following terms to the subject of the Civil War.
DanielleElmas [232]
What following terms I don’t see any please make your question clear
4 0
3 years ago
The objective lens and the eyepiece of a telescope are spaced 85 cm apart. If the eyepiece is123 D what is the total magnificati
dedylja [7]

Answer:

The magnification would be "103.55". A further explanation is given below.

Explanation:

The given values are:

Distance between lens and eyepiece,

L = 85 cm

Eyepiece is,

= 123 D

Now,

The refractive power of eye piece will be:

⇒ \frac{1}{f_e}=123D

   f_e=\frac{1}{123D}

   f_e=0.813 \ cm

The length of the telescope will be:

⇒ L=f_0+f_e

⇒ f_0=L-f_e

On substituting the values, we get

⇒     =85-0.813

⇒     =84.187 \ cm

Now,

The magnification of the telescope will be:

⇒ M=\frac{f_0}{f_e}

⇒      =\frac{84.187}{0.813}

⇒      =103.55

5 0
2 years ago
Which of these demonstrates the most sportsman-like statement?
Len [333]
What are the choices?
5 0
3 years ago
In the late 19th century, great interest was directed toward the study of electrical discharges in gases and the nature of so-ca
svlad2 [7]

Answer:

a) He found the same value of q/m for different cathode materials.

b)      y = - \frac{e}{m}\  \frac{E_o v_o^2 }{2d^2} ,  c)  v = \frac{E_o}{B_o}

Explanation:

In Thomson's experiments he was able to measure the deflection of the light beam under the effect of the magnetic field and with these results find the e / m relationship, which in all cases is the same, therefore the most important conclusion is that the value e E / m is constant for all materials.

b) In the part of the plates the electrons are accelerated by the electric field,

              F = ma

             - e E = m a

              a = - (e/m)  E₀

               

the distance traveled is          

X axis

          x = v₀ t

the separation of the plates is x = d

          t = vo / d

               

Y axis

          y = v_{oy} t + ½ to t²

          y = ½ a t²

          y = - \frac{e}{m}\  \frac{E_o v_o^2 }{2d^2}

           

c) In this case there is a magnetic field B₀ and the electrons have no deflection

         F = - e E + e v x B

       

if there is no deviation F = 0

         e E = e v B

         v = \frac{E_o}{B_o}

5 0
3 years ago
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