Answer:
The partial pressure of nitrogen is 597.5 torr
Explanation:
Step 1: Data given
Mol fraction of N = 0.781
Mol fraction of O = 0.209
Mol fraction Ar = 0.010
Atmospheric pressure = 765.0 torr
The partial pressure is given by Pi = Xi * Pt
⇒ χ
i = the mole fraction of gas i in the mixture
⇒ P
total = the total pressure of the mixture
Step 2: Calculate the partial pressure of nitrogen
P(N) = mol fraction of N * atmospheric pressure
P(N) = 0.781 * 765.0 torr = 597.5 torr
The partial pressure of nitrogen is 597.5 torr
An object keeps the same amount of kinetic energy unless it speeds up or slows down.
Kinetic energy can be calculated for any moving object as long as the objects' mass and speed are known.
The unit used when measuring kinetic energy is called a joule.
Kinetic energy can occur in any direction whether up and down or left to right.
Substance A will sink because it is more dense than water. An object that is more dense than water will sink and an object that is less dense than water will float.
Answer:
0.088 M.
Explanation:
Assuming that the temperature is 429 K, we can calculate the concentration of NO₂. Kc(429K) = 0.490.
The reaction is:
N₂O₄(g) ⇄ 2NO₂(g)
0.04 0.04
0.04 - x 0.04 + 2x
The constant of the reaction is:
![Kc = \frac{[NO_{2}]^{2}}{[N_{2}O_{4}]]}](https://tex.z-dn.net/?f=%20Kc%20%3D%20%5Cfrac%7B%5BNO_%7B2%7D%5D%5E%7B2%7D%7D%7B%5BN_%7B2%7DO_%7B4%7D%5D%5D%7D%20)
By solving the above equation for x we have:
x = 0.024 = [NO₂]
Hence the concentration of NO₂ is:
![[NO_{2}] = 0.04 + 2*0.024 = 0.088 M](https://tex.z-dn.net/?f=%20%5BNO_%7B2%7D%5D%20%3D%200.04%20%2B%202%2A0.024%20%3D%200.088%20M%20)
I hope it helps you!
Answer: I believe the correct answer is C. 41 degrees Fahrenheit.
Explanation: Time and temperature are the most essential elements for monitoring the growth of disease-causing bacteria in food. The temperature danger zone lies between 40 degrees Farenheit and 140 degress Fahrenheit.
Hope this helps! ^^
