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Drupady [299]
3 years ago
14

an object of mass 0.5kg at rest, started to fall aheigh of 180cm from the surface of earth. it's momentum when it reaches the ea

rth's surface is​
Physics
1 answer:
kupik [55]3 years ago
4 0

Answer:

m=0.5kg

h = 180 cm =1.8 mh=180cm=1.8m

Initial potential energy of the object is:

E_p=m*g*hE

p

​ =m∗g∗h

Kinetic energy at the surface:

E_k=\frac{mv^2}{2}E

k

​  =

2

mv

2

According to the law of conservation of energy (assuming no air resistance):

E_p = E_kE

p

​  =E

k

​mgh=\frac{mv^2}{2}mgh=

2

mv

2

Solving for v:

v=\sqrt{2gh}v=

2gh

​

p=mvp=mv

So,

p= m*v = m\sqrt{2gh}p=m∗v=m

2gh

​

Calculating:

p= 0.5\sqrt{2*9.8*1.8}\approx 2.97 \frac{kg*m}{s}p=0.5

2∗9.8∗1.8

​ ≈2.97

s

kg∗m

​ Answer:

p \approx 2.97 \frac{kg*m}{s}p≈2.97

s

kg∗m

​

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Helium gas contained in a piston cylinder assembly undergoes an isentropic polytropic process from the given initial state with
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Answer:

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⇒ ΔQ = 0

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