The weight of an object is given by:
where m is the mass and g is the gravitational acceleration.
Miguel's mass is the same on every planet (m=60 kg), the only element changing in the formula is g, the value of the gravitational acceleration, which is different for every planet. So by knowing the ratio , where g is the gravitational acceleration on Earth and is the value of the gravitational acceleration on the planet we are studying, we can calculate the ratio , where W is Miguel's weight on Earth (which we know, it is W=132 lbs), and Wx is the weight on the planet we are studying:
- For the Moon, we have
so the weight on the Moon is
- For Neptune, we have
so the weight on Neptune is
- For Mercury, we have
so the weight on Mercury is
Answer:
I think the answer is 18 km/h
Explanation:
Explanation:
7) Given:
v₀ = 2.0 m/s
v = 0 m/s
t = 3.00 s
Find: Δx
Acceleration isn't included in the problem, so use a kinematic equation that doesn't involve a.
Δx = ½ (v + v₀) t
Δx = ½ (0 m/s + 2.0 m/s) (3.00 s)
Δx = 3.0 m
8) Given:
v₀ = 0 m/s
v = 5 m/s
t = 4 s
Find: a
Displacement isn't included in the problem, so use a kinematic equation that doesn't involve Δx.
v = at + v₀
5 m/s = a (4 s) + 0 m/s
a = 1.25 m/s²
9) Given:
v_avg = Δx / t
0.5 m/s = 8 m / t
t = 16 s
Climatology is a subspecialty of B) Meteorology.