Integrating the velocity equation, we will see that the position equation is:

<h3>How to get the position equation of the particle?</h3>
Let the velocity of the particle is:

To get the position equation we just need to integrate the above equation:


Then:


Replacing that in our integral we get:


Where C is a constant of integration.
Now we remember that 
Then we have:

To find the value of C, we use the fact that f(0) = 0.

C = -1 / 3
Then the position function is:

Integrating the velocity equation, we will see that the position equation is:

To learn more about motion equations, refer to:
brainly.com/question/19365526
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The heat energy transferred by the iron nail is 4680 J
Explanation:
The thermal energy transferred by a substance to another substance is given by the equation

where
m is the mass of the substance
C is its specific heat capacity
is its change in temperature
For the iron nail in this problem, we have:
m = 16 g


So, the amount of heat energy given off by the nail is

where the negative sign indicates that the heat is given off.
Learn more about specific heat capacity:
brainly.com/question/3032746
brainly.com/question/4759369
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<span>Color blindness is the failure of the red sensitive nerves in the eye that don't respond to light properly.</span>
Answer:
If the line is curved, the slope is changing, which also means the velocity is changing. In a distance-time graph, the gradient of the line is equal to the speed of the object. The more the gradient (and the steeper the line) the faster the object is moving.
Answer:
It relaxes
Explanation:
I took the test I hope it helps