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aniked [119]
2 years ago
7

Let theta denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the Bob is m, the

n the tension in string is

Physics
2 answers:
posledela2 years ago
8 0
The tension has to hold the part of the weight in the direction of the string:

T = mg*cos(theta)

Theta=0, whole weight, theta=90, T=0, if the pendulum is horizontal, the string will be loose! Yeah
Harrizon [31]2 years ago
6 0

Answer:

So the tension  in the string T =mg cosθ

Explanation:

Now given that

mass of bob = m

Angle from vertical plane =θ

Lets T is the tension in the string

From the diagram

Weight of bob have two component ,first one(mg cosθ) balance the tension in the string and other one(mg sinθ)  make the bob to move in the plane.

So the tension  in the string T =mg cosθ

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The critical angle for a special type of glass in air is 30.8 ◦ . the index of refraction for water is 1.33. what is the critica
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In the first part of the problem, light moves from glass to air (n_a=1.00) and the critical angle is \theta_c = 30.8^{\circ}. This means that we can find the refractive index of glass by re-arranging the previous formula:
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