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aniked [119]
3 years ago
7

Let theta denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the Bob is m, the

n the tension in string is

Physics
2 answers:
posledela3 years ago
8 0
The tension has to hold the part of the weight in the direction of the string:

T = mg*cos(theta)

Theta=0, whole weight, theta=90, T=0, if the pendulum is horizontal, the string will be loose! Yeah
Harrizon [31]3 years ago
6 0

Answer:

So the tension  in the string T =mg cosθ

Explanation:

Now given that

mass of bob = m

Angle from vertical plane =θ

Lets T is the tension in the string

From the diagram

Weight of bob have two component ,first one(mg cosθ) balance the tension in the string and other one(mg sinθ)  make the bob to move in the plane.

So the tension  in the string T =mg cosθ

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Two people are talking at a distance of 3.0 m from where you are, and
tigry1 [53]

Answer:

The sound intensity that the other student measure, I₂ is expected to be;

A) 6.2 × 10⁻⁸ W/m²

Explanation:

The measure of sound intensity is given by the following formula;

I = \dfrac{P}{4 \cdot \pi \cdot R^2}

\dfrac{I_2}{I_1} = \dfrac{R_1^2}{R_2^2}

Where;

I = The intensity

R = The radius

P = The power of the sound

Whereby we have;

The distance of the two people talking, R₁ = 3.0 m

The measure of the sound intensity, I₁ = 1.1 × 10⁻⁷ W/m² (from an online source)

The distance of the other student from the two people talking, R₂ = 4.0 m

Therefore, the estimate of the sound intensity, I₂, is given as follows;

{I_2} = \dfrac{R_1^2}{R_2^2} \times {I_1}

{I_2} = \dfrac{(3.0 \, m)^2}{(4.0 \, m)^2} \times 1.1 \times 10^{-7} \ W/m^2 = 6.1875 \times 10^{-8} \ W/m^2

I₂ = 6.1875 × 10⁻⁸ W/m²

∴ The sound intensity that the other student measure, I₂ ≈ 6.2 × 10⁻⁸ W/m²

5 0
3 years ago
An LR circuit contains an ideal 60-V battery, a 51-H inductor having no resistance, a 21-Ω resistor, and a switch S, all in ser
mars1129 [50]

Answer:

current in the circuit is 1.428 A

Explanation:

Given data

voltage = 60 V

resistor = 21 Ω

time = 0

to find out

current in the circuit

solution

we have given that

voltage across the resistor = voltage across the inductor

that is = 60 /2 = 30 V

we know voltage across resistor = IR

so I × R = V/2

and current I = 30 /21

so current = 1.428 A

current in the circuit is 1.428 A

8 0
3 years ago
A member of the marching band tunes their trombone inside their school. When they walk out to the field the instrument goes out
Alona [7]

The best explanation is the <em>difference</em> between the inside <em>temperature</em> and the outside temperature.

If the player doesn't change his emboucher (muscles and position of his lips), then the pitch produced by the instrument depends only on the physical dimensions of its plumbing, and the speed of sound in the tube.

BOTH of those things change slightly when the temperature changes.

4 0
3 years ago
Read 2 more answers
car travels 80 meters due north in 12 seconds then the car turns around and travels 30 Mi do South in 4 seconds calculate the av
Zinaida [17]

Answer:

1) 3.1 m/s

2) 7 m/s

Explanation:

Distance due north = 80 m

Distance due south = 30 m

Distance between north and south = (80 - 30) m = 50 m

Total time = (12 + 4) sec = 16 sec

1) Average speed = 50/16 = 3.1 m/s

2) Average velocity = Total distance/total time = (80 + 30) m/16 s = 110/16 = 7 m/s

8 0
3 years ago
When the mass of the cylinder increased by a factor of 3, from 1.0 kg to 3.0 kg, what happened to the cylinder’s gravitational p
const2013 [10]

Answer: Fourth option. It increased by a factor of 3.

Solution:

m1=1.0 kg

Cylinder's gravitational potential energy: Ep=m*g*h

Ep1=(1.0 kg)*g*h

Ep1=g*h

m2=3.0 kg

Ep2=(3.0 kg)*g*h

Ep2=3*g*h

Replacing g*h by Ep1 in the equation above:

Ep2=3*Ep1

Then, the cylinder's gravitational potential energy increased by a factor of 3.

3 0
3 years ago
Read 2 more answers
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