Question

For the reaction between ammonium phosphate and lead (IV) nitrate, producing ammonium nitrate and lead (IV) phosphate, how many moles of lead (IV) nitrate would be needed to produce 11.75 moles of ammonium nitrate

Answer 1

Answer:

2.938 mol Pb(NO₃)₄

Explanation:

Step 1: Given data

• Moles of NH₄NO₃ to be produced: 11.75 mol

• Moles of Pb(NO₃)₄: ?

Step 2: Write the balanced equation

4 (NH₄)₃PO₄ + 3 Pb(NO₃)₄ = Pb₃(PO₄)₄ + 12 NH₄NO₃

Step 3: Calculate the number of moles of Pb(NO₃)₄required to produce 11.75 moles of NH₄NO₃

The molar ratio of Pb(NO₃)₄ to NH₄NO₃ is 3:12.

11.75 mol NH₄NO₃ × (3 mol Pb(NO₃)₄/12 mol NH₄NO₃) = 2.938 mol Pb(NO₃)₄