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joja [24]
3 years ago
14

For the reaction between ammonium phosphate and lead (IV) nitrate, producing ammonium nitrate and lead (IV) phosphate, how many

moles of lead (IV) nitrate would be needed to produce 11.75 moles of ammonium nitrate
Chemistry
1 answer:
NemiM [27]3 years ago
3 0

Answer:

2.938 mol Pb(NO₃)₄

Explanation:

Step 1: Given data

  • Moles of NH₄NO₃ to be produced: 11.75 mol
  • Moles of Pb(NO₃)₄: ?

Step 2: Write the balanced equation

4 (NH₄)₃PO₄ + 3 Pb(NO₃)₄ = Pb₃(PO₄)₄ + 12 NH₄NO₃

Step 3: Calculate the number of moles of Pb(NO₃)₄required to produce 11.75 moles of NH₄NO₃

The molar ratio of Pb(NO₃)₄ to NH₄NO₃ is 3:12.

11.75 mol NH₄NO₃ × (3 mol Pb(NO₃)₄/12 mol NH₄NO₃) = 2.938 mol Pb(NO₃)₄

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Answer:

NH4NO3

Explanation:

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2 years ago
Calculate the number of grams nitric acid (HNO3) in 375 L of a 1.00 M solution.
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6 0
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Na2CO3(aq)+2HCl(aq)→2NaCl(aq)+H2O(l)+CO2(g) A student combined two colorless aqueous solutions. One of the solutions contained N
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7 0
3 years ago
Can someone please help me understand this?
Nataliya [291]

Answer:

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alt

Figure 11.5.1: As a container of confined gas is heated, its molecules increase in kinetic energy and push the movable piston outward, resulting in an increase in volume.

Mathematically, the direct relationship of Charles's Law can be represented by the following equation:

V

T

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As with Boyle's Law, k is constant only for a given gas sample. The table below shows temperature and volume data for a set amount of gas at a constant pressure. The third column is the constant for this particular data set and is always equal to the volume divided by the Kelvin temperature.

Explanation:

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4 0
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After undergoing alpha decay, an atom of radium-226 becomes
Zanzabum
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8 0
3 years ago
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