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2 years ago

The following reaction shows sodium hydroxide reacting with sulfuric acid.

Chemistry

1 answer:

elena-14-01-66 [18.8K]2 years ago

4 0

The amount of Na₂SO₄ would be 15.09 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

4NaOH + 2H₂SO₄ --> 2Na₂SO₄ + 4H₂O

Mole ratio of NaOH and Na₂SO₄ = 2:1

Mole of 8.50 grams of NaOH = 8.50/40

= 0.21 mole

Equivalent mole of Na₂SO₄ = 0.21/2

= 0.11 mole

Mass of 0.11 mole Na₂SO₄ = 0.11 x 142.04

= 15.09 grams

More on stoichiometric reactions can be found here: brainly.com/question/8062886

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