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vladimir1956 [14]
3 years ago
7

Veronica claims that she can throw a dart at a dartboard from a distance of 2 m and hit the 5 cm wide bullseye if she throws the

dart horizontally with a speed of 15 m/s. She starts the throw at the same height las the top of the bulls-eye. Is she able to hit the bullseye?
Physics
1 answer:
wariber [46]3 years ago
3 0
First, find the amount of time for the dart to hit the board using this equation: t = d/v

t = 2 m/ 15 m/s = 0.133 s

Then, find the height the dart has fallen from its initial point using this equation: h = 0.5gt²

h = 0.5(9.81 m/s²)(0.133 s)² = 0.0872 m or 8.72 cm

Since the diameter of the bull's eye is only 5 cm, and you started at the same level of the top of the bull's eye, that means the maximum allowance would only be 5 cm. Since it exceeded to 8.72 cm, it means that <em>Veronica will not hit the bull's eye.</em>
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A 49.3 g ball of copper has a net charge of 2.0 µc. what fraction of the copper's electrons has been removed? (each copper atom
Serggg [28]
First, find how many copper atoms make up the ball: 
 moles of atoms = (49.3 g) / (63.5 g per mol of atoms) = 0.<span>77638</span><span>mol 
</span> # of atoms = (0.77638 mol) (6.02 × 10^23 atoms per mol) = 4.6738*10^23<span> atoms </span>

<span> There is normally one electron for every proton in copper. This means there are normally 29 electrons per atom:
</span> normal # electrons = (4.6738 × 10^23 atoms) (29 electrons per atom) = <span> <span>1.3554</span></span><span>× 10^25 electrons 
</span>
<span> Currently, the charge in the ball is 2.0 µC, which means -2.0 µC worth of electrons have been removed.
</span><span> # removed electrons = (-2.0 µC) / (1.602 × 10^-13 µC per electron) = 1.2484 × 10^13 electrons removed
 
</span><span> # removed electrons / normal # electrons = </span>
<span>(1.2484 × 10^13 electrons removed) / (1.3554 × 10^25 electrons) = 9.21 × 10^-13 </span>

<span> That's 1 / 9.21 × 10^13 </span>
7 0
3 years ago
Its like almost 12 pm rn and i have school tomorrow so i dunno why im still up but i just wanna know how big the world is. like
tatiyna
The earth all the way around is 196.9 million miles
7 0
3 years ago
What value should be reported for the total mass of three samples of iron weighing 117.0 g, 19.43 g, and 6.1043 g?
AURORKA [14]

The value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g

<h3>What is Mass and Weight ?</h3>

Mass is the quantity of matter. While weight is a gravitational pull on an object. Mass is measured in Kg while weight is measured in Newton.

What value should be reported for the total mass of three samples of iron weighing 117.0 g, 19.43 g, and 6.1043 g?

The total mass will be the sum of the three masses.

The total mass = 117 + 19.43 + 6.1043

The total mass = 142.5343 g

Convert gram to kilogram by dividing the answer by 1000

The total mass = 142.5343/1000

The total mass = 0.1425343 Kg

Therefore, the value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g approximately

Learn more about Mass and Weight here: brainly.com/question/1384116

#SPJ1

5 0
1 year ago
two vectors have a magnitude of 2.5km and 6.5 km . Predict the maximum and minimum magnitudes of their resultant vector
agasfer [191]

The maximum magnitude of their resultant vector is when the two vectors are parallel and in the same direction, so they lie on the same axis. In this case, the magnitude of their resultant vector is simply the sum of the two magnitudes:

R=2.5 km+6.5 km=9.0 km


The minimum magnitude of their resultant vector is when the two vectors are parallel but in opposite direction. In this case, the magnitude of their resultant vectors is just the difference between the two magnitudes:

R=6.5 km-2.5 km=4.0 km

8 0
3 years ago
A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average forc
Natali5045456 [20]

Answer:

<h2>9.3kN</h2>

Explanation:

Step one:

given data

mass of bullet= 0.02kg

speed v=700m/s

time taken =1.5ms= 0.0015 seconds

Step two:

we know that from the first law

F=ma-----1  first law of motion

also, we know that

a=v/t----2

put a=v/t in equation 1 we have

F=mv/t

Step three:

substitute our given data to find force

F=0.02*700/0.0015

F=14/0.0015

F=9333.33N

F=9.3kN

<u>The average force exerted is 9.3kN</u>

7 0
3 years ago
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