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german
3 years ago
11

Please answer these questions for me! I am giving MAX points! Brainliest!

Physics
2 answers:
guajiro [1.7K]3 years ago
3 0

I think you have them all marked correctly

7. They carry hereditary material from parent

8. 50 percent

1. Nutrition

2. X-linked dominant


If Im wrong Im sorry. its been like 4 years since i took biology but i remember some things

Wittaler [7]3 years ago
3 0

1) Is correct

2) Is also correct

7) IS ALSO CORRECT

8) IS ALSO CORRECT LOL THEY'RE RIGHT

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ANSWER THE 3 QUESTION WILL MARK AS BRAINLIEST THIS IS 20 POINTS :)))
PtichkaEL [24]
15) a 
16) b
17) a

Hope this helps
3 0
3 years ago
Read 2 more answers
A) 1.2-kg ball is hanging from the end of a rope. The rope hangs at an angle 20° from the vertical when a 19 m/s horizontal wind
Marat540 [252]

Answer:

Part a)

F_v = 4.28 N

Part B)

L = 1.02 m

Part C)

v = 1.25 m/s

Explanation:

Part A)

As we know that ball is hanging from the top and its angle with the vertical is 20 degree

so we will have

Tcos\theta = mg

T sin\theta = F_v

\frac{F_v}{mg} = tan\theta

F_v = mg tan\theta

F_v = 1.2\times 9.81 (tan20)

F_v = 4.28 N

Part B)

Here we can use energy theorem to find the distance that it will move

-\mu mg cos\theta L + mg sin\theta L = -\frac{1}{2}mv^2

(-(0.37)m(9.81) cos15 + m(9.81) sin15)L = - \frac{1}{2}m(1.4)^2

(-3.5 + 2.54)L = - 0.98

L = 1.02 m

Part C)

At terminal speed condition we know that

F_v = mg

bv^2 = mg

2.5 v^2 = 3.9

v = 1.25 m/s

7 0
2 years ago
I need help with the graphs
Viefleur [7K]
For heating Solid, Liquid, Gas and for cooling the opposite Gas, Liquid, Solid
8 0
3 years ago
The drawings show two examples in which a ray of light is refracted at the interface between two liquids. In each example the in
Nataly [62]

Answer:

Possible options:

A. nA, nC, nB

B. nA, nB, nC

C. nC, nB, nA

D. nC, nA, nB

E. nB, nA, nC

Answer is D

Explanation:

When the light is refracted into liquid B it is bent away from the normal, so that nA > nB. When the light is refracted into liquid C it is bent toward the normal, so that nC > nA. Therefore, we conclude that nC > nA > nB

6 0
2 years ago
At t= 0, a particle moving in the xy plane with constant acceleration has a velocity of Vi= (3.00i -2.00j) m/s and is at the ori
ivanzaharov [21]

Answer:

(a) a = (2i + 4.5j) m/s^2

(b) r = ro + vot + (1/2)at^2

Explanation:

(a) The acceleration of the particle is given by:

\vec{a}=\frac{\vec{v}-\vec{v_o}}{t}\\\\

vo: initial velocity = (3.00i -2.00j) m/s

v: final velocity = (9.00i + 7.00j) m/s

t = 3s

by replacing the values of the vectors and time you obtain:

\vec{a}=\frac{1}{3s}[(9.00-3.00)\hat{i}+(7.00-(-2.00))\hat{j}]\\\\\vec{a}=(2\hat{i}+4.5\hat{j})m/s^2

(b) The position vector is given by:

\vec{r}=\vec{r_o}+\vec{v_o}t+\frac{1}{2}\vec{a}t^2

where vo = (3.00i -2.00j) m/s and a = (2.00i + 4.50j)m/s^2

4 0
2 years ago
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