Answer:
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The answer is equilibrium.
This is what is called dynamic equilibrium. It is the most common form of equilibrium in chemistry. It means that in average the system is not changing but if you look particle by particle they are changing. Giving that the rate at which the parciles pass from phase A to phase B is the same at which the particle pass from phase B to phase B, the system does not change, i.e. it is in equilibrium.
It is chemical change I got that answer right on my test
Unpaired electrons are those electrons which exist singly in orbital, without making pair with other electron
CALCIUM:
Atomic Number 20
Electronic Configuration; 1s², 2s², 2p⁶, 3s², 3p⁶, 4s²
Number of Unpaired e⁻s; Zero
ARGON:
Atomic Number 18
Electronic Configuration; 1s², 2s², 2p⁶, 3s², 3p⁶
Number of Unpaired e⁻s; Zero
ALUMINIUM:
Atomic Number 13
Electronic Configuration; 1s², 2s², 2p⁶, 3s², 3p¹ (Ground State)
Electronic Configuration; 1s², 2s², 2p⁶, 3s¹, 3px¹, 3py¹ (Excited State)
Number of Unpaired e⁻s; 1 in Ground state and 3 in Excited State.
CARBON:
Atomic Number 6
Electronic Configuration; 1s², 2s², 2px¹, 2py¹ (Ground State)
Electronic Configuration; 1s², 2s¹, 2px¹, 2py¹, 2pz¹ (Excited State)
Number of Unpaired e⁻s; 2 in Ground state and 4 in Excited State
Answer: c. 0.200 m HOCH2CH2OH
Explanation:
The collective properties of solvents expressed that the freezing point of water is lowered when solute particles are dissolved in it.
When more particles are dissolved, the more the freezing point is deepened and lowered.
Here, all the molarities are equal, the deciding factor in measuring the lowering will be which substance produces the fewest particles in solution; then we relate it to lowering of the freezing point.
Ba(NO3)2 ---> Ba2+ + 2NO3(1-)
1 mol releases 3 mol of ions.
Mg(ClO4)2 ---> Mg2+ + 2ClO4(1-)
1 mol releases 3 mol of ions.
HOCH2CH2OH is covalent and doesn't ionize.
1 mol in water is just 1 mol of molecules.
Na3PO3 ---> 3Na+ + PO3(1-)
1 mol releases 4 mol ions.
The substance that produces the fewest particles in solution is the 0.200 m HOCH2CH2OH