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dangina [55]
2 years ago
14

Consider the following equilibrium: 2SO2(g) + O2(g) 2SO3(g) Which of the following is a correct equilibrium expression? Keq=[SO3

][SO2][O2] Keq=[SO3]2[SO2]2[O2] Keq=[SO2][O2][SO3] Keq=[SO2]2[O2][SO3]2
Chemistry
1 answer:
Ne4ueva [31]2 years ago
7 0
Answer : Option B) K_{eq}  =  \frac{[SO_{3}]^{2}  }{[SO_{3}]^{2} . [O_{3}]^{2}}

Explanation : The equilibrium constant is often expressed in terms of the molar concentration of products divided by the product of molar concentrations of reactants.

So, K_{eq} =  \frac{[products]}{[reactants]}.

Now, here in the given reaction of  

2SO_{2}  + O_{2} ----\ \textgreater \  2SO_{3}

So, we have the equation for equilibrium as K_{eq} = \frac{[SO_{3}]^{2} }{[SO_{3}]^{2} . [O_{3}]^{2}}
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in example 5.11 of the text the molar volume of n2 at STP is given as 22.42 L/mol how is this number calculatd how does the mola
Valentin [98]

Answer:

V = 22.42 L/mol

N₂ and H₂ Same molar Volume at STP

Explanation:

Data Given:

molar volume of N₂ at STP = 22.42 L/mol

Calculation of molar volume of N₂ at STP  = ?

Comparison of molar volume of H₂ and N₂ = ?

Solution:

Molar Volume of Gas:

The volume occupied by 1 mole of any gas at standard temperature and pressure and it is always equal to 22.42 L/ mol

Molar volume can be calculated by using ideal gas formula  

                               PV = nRT

Rearrange the equation for Volume

                            V = nRT / P . . . . . . . . . (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

Standard values

P = 1 atm

T = 273 K

n = 1 mole

R = 0.08206 L.atm / mol. K

Now put the value in formula (1) to calculate volume for 1 mole of N₂

                   V = 1 x 273 K x 0.08206 L.atm / mol. K / 1 atm

                   V = 22.42 L/mol

Now if we look for the above calculation it will be the same for H₂ or any gas. so if we compare the molar volume of 1 mole N₂ and H₂ it will be the same at STP.

6 0
3 years ago
A sample of nitrogen occupies 10.0 liters at 25°C what would be the new volume at 20°C? 7.9 L Ob 9.8 L 10.2 L 10.6 L
PtichkaEL [24]

Answer:

  9.4 liter

Explanation:

1) Data:

V₁ = 10.0 L

T₁ = 25°C = 25 + 273.15 K = 298.15 K

 P₁ = 98.7 Kpa

 T₂ = 20°C = 20 + 273.15 K = 293.15 K

  P₂ = 102.7 KPa

  V₂ = ?

2) Formula:

Used combined law of gases:

  PV / T = constant

  P₁V₁ / T₁ = P₂V₂ / T₂

3) Solution:

Solve the equation for V₂:

  V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

V₂ = P₁V₁ T₂ / (P₂ T₁)

V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)

V₂ =  9.4 liter ← answer

You can learn more about gas law problems reading this other answer on

Explanation:

7 0
2 years ago
Can you please help me (50 points)
Anna35 [415]

Answer:

P=15

N=59

Explanation:

Pic is blurry but I based my answer on bottom number being 74

4 0
2 years ago
How is it that an electron can cause your brain to “see” color without ever leaving its atom?
iogann1982 [59]
Light receptors with in the eye transmit messages to the brain, which procedures is the familiar sensations of color. Newton observed that color is not inherit in objects. Rather the surface of an object reflects some colors and absorbs all the others. We perceive only the reflective colors.
4 0
3 years ago
The image shows copper wire coiled around an iron nail and connected to a battery to create an electromagnet. Which will increas
Ulleksa [173]
A is the correct answer and this question should be in physics not chemistry
8 0
3 years ago
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