Answer:
make sure that the number of atoms on the left side of the equation equals the number of atoms on the right.
Explanation:
Answer:
The new volume of a gas at 750 mmhg and with a volume of 2. 00 l when allowed to change its volume at constant temperature until the pressure is 600 mmhg is 2.5 Liters.
Explanation:
Boyle's law states that the pressure of a given amount of gas is inversely proportional to it's volume at constant temperature. It is written as;
P ∝ V
P V = K
P1 V1 = P2 V2
Parameters :
P1 = Initial pressure of the gas = 750 mmHg
V1 = Initial pressure of the gas = 2. 00 Liters
P2 = Final pressure of the gas = 600 mmHg
V2 = Fimal volume of the gas = ? Liters
Calculations :
V2 = P1 V1 ÷ P2
V2= 750 × 2. 00 ÷ 600
V2 = 1500 ÷ 600
V2 = 2.5 Liters.
Therefore, the new volume of the gas is 2. 5 Liters.
Part 1: Calculate the percent ionization of 0.0075 m butanoic acid (Ka=1.5x10^-5)
C4H8O2(aq) +H2O(l) → C4H7O2(aq) + H3O +
initial 0.0075 0 0
change -X +X +X
final 0.0075-X X X
when Ka is relative smaller to the intial concentration of the acid so we can assume that 0.0075-X≈ 0.0075 by substitution in Ka formula:
Ka = [C4H7O2][H3O+] / [C4H8O2]
1.5x10^-5 = X*X / 0.0075
X^2 = 1.125x10^-7
X= 0.00034 m =3.4 x 10 ^-4 m
∴ [C4H7O2] = [H3O+] = 3.4X10^-4
∴ percent ionization = [H+ equlibrium]/[acid initial] *100
= 3.4X10^-4/0.0075 * 100
= 4.5 %
part 2) calculate the percent ionization of 0.0075m butanoic acid in a solution containing 0.085m sodium butanoic?
C4H8O2(aq) + H2O(l) ↔ C4H7O2(aq) + H3O+
initial 0.0075 0 0.085
change -X +X +X
final 0.0075-X X 0.085+X
we can assume that 0.0075-X≈ 0.0075 & 0.085+X ≈ 0.085
∴Ka = (X*(0.085)) / (0.0075)
(1.5x10^-5)*0.0075 = 0.085X
∴X = 1.3x 10^-6
∴ percent ionization = (1.3x10^-6)/0.0075 * 100 = 0.017 %
Answer:
305.65 K
Explanation:
Celsius to Kelvin => + 273.15
32.5 + 273.15
= 305.65 K