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sweet [91]
3 years ago
5

What is the volume of a 0.5 mol/L NaOH solution required to completely react with 20 mL of a 2.0 mol/L HCl solution? What is the

pH value of the produced solution? (Hint: Write and balance the chemical reaction between HCl and NaOH, and then use the stoichiometric relation (molar relation) between NaOH and HCl to calculate the minimum volume of NaOH solution.) Group of answer choices
Chemistry
1 answer:
wel3 years ago
6 0

Answer:

The volume of NaOH required is 80mL

pH of the resulting solution is 7 since reaction produces a normal salt

Explanation:

First, we generate a balanced equation for the reaction as shown below:

NaOH + HCl —> NaCl + H2O

From the equation,

nA = 1

nB = 1

From the question,

Ma = 2.0 mol/L

Va = 20 mL

Mb = 0.5 mol/L

Vb =?

MaVa / MbVb = nA /nB

2x20 / 0.5 x Vb = 1

0.5 x Vb = 2 x 20

Divide both side by 0.5

Vb = (2 x 20)/0.5

Vb = 80mL

The volume of NaOH required is 80mL

Since the reaction involves a strong acid and a strong base, a normal salt solution will be produced which is neutral to litmus paper. So since the salt solution is neutral to litmus paper then the pH of the resulting solution is 7

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4 years ago
Copper sulfate can crystalize as an anhydrate (no water in the crystal) or as three different hydrates (varying amounts of water
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Answer:

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B. Also it binds nicely with the sediments  or the crystal.

Explanation:

As it is mentioned here that copper sulphate can be crystallized as an anhydrate which means that their  is no waterin those crystals or can be as of those three different hydrates whose crystal structure varies with the amount of water present in it.

The four forms are also given of the copper sulphate are:

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So, the two factors that might give an affect which type of copper sulphate  mineral willoccur at a given location is:

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8 0
3 years ago
PLEASE HELP:<br><br> iron reacts with nitrogen to form iron(III) nitride
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Answer:

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Explanation:

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Answer:

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The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

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5 0
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