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Paul [167]
3 years ago
12

Which image shows 2-hexyne?

Chemistry
1 answer:
MaRussiya [10]3 years ago
4 0

Answer: C

Explanation:

A. Shows 3-Hexyne (NOT 2-HEXYNE)

B. Shows 7 carbons (too many) (NOT 2-HEXYNE)

C. Shows a triple bond (yne) and 6 carbons and it's on the second carbon (2-HEXYNE)

D. Shows two substitent on the second carbon but the triple bond is on the 3rd carbon so it's 2,2-dimethyl-3-heptyne (NOT 2-HEXYNE)

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One of the particles in an atom is the proton. A proton has a radius of
Charra [1.4K]

Answer:

Density = 4.06 * 10^14

Explanation:

Givens

r = 1 * 10^-13 cm

m = 1.7 * 10^-24 grams

Formula

V = 4/3 * pi * r^3

D = m/V

Solution

Put the givens into the formula.

V = (4/3) 3.14 * (1 * 10^-13)^3          Find the value for r^3

V = (4/3) 3.14 * 1 * 10^-39               Find the volume. Indicate divide by 3

V = 1.256 10^-38/3

V = 4.1867 * 10^-39

Density = m / v

Density = 1.7*10^-24/4.1867*10^-39  Do the division

Density = .406 * 10^(-24 + 39)

Density = .406 * 10^15 grams/ cm^3

Answer: Density = 4.06 * 10^14

5 0
2 years ago
A balloon contains 7.36 g of oxygen gas (O2). How many oxygen molecules are in the balloon?
Firlakuza [10]
Avagadros constant states that 1 mol of any substance is made of 6.022 x 10^23 units.
These units could be atoms making up elements or molecules making up compounds.
1 mol of molecular oxygen (O2) is made of 6.022 x 10^23 molecules of O2
The mass of 1 mol of O2 is 32 g/mol
This means that the number of oxygen molecules in 32 g are 6.022 x 10^23 molecules
Therefore in 7.36 g of oxygen gas there are - 6.022 x 10^23 /32 g/mol x 7.36 g = 1.39 x 10^23 oxygen molecules
Answer is 1.39 x 10^23 oxygen molecules
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