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3 years ago

How is momentum conserved in a Newton's cradle when one steel ball hits the other?

2 answers:

6 0

Momentum is conserved when you pull one ball bearing back in the air before letting it go to hit the others. Think about it. You lift the bearing in the air with all it's weight, thus leading it to build up momentum and conserve it. Then once you release it, it transfers the energy through the other bearings and out onto the other side repeating it's process.

KatRina [158]3 years ago

5 0

All the momentum starts in one ball, and after the collision, it is all in the other ball.

I took the test

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Which sentence is a scientific statement?

tekilochka [14]

Answer:d

Explanation:

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2 years ago

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(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of

gregori [183]

Detonation of nitroglycerin:

$4C_3H_5N_3O_9 ------\ \textgreater \ 12CO_2+6N_2+O_2+H_2O$

Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g

Moles = mass / molar mass = 3.184 g/ 227.0872 g/mol = 0.01402

the ratio between nitroglycerin and Carbon dioxide is 4 : 12
So, moles CO2 = 0.01402 x 12 / 4 =0.0420

the ratio between nitroglycerin and N2 is 4 : 6
moles N2 = 0.01402 x 6 / 4 =0.0841

the ratio between nitroglycerin and O2 is 4 : 1 
moles O2 = 0.01402 x 1 / 4 = 0.0035

the ratio between nitroglycerin and water is 4 : 1 
in the same way moles water = 0.005258 

total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758

0.130758 x 55 = 5.78 L 

Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g

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2 years ago

when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced

Maksim231197 [3]

Answer:

16.02 g

Explanation:

the balanced equation for the decomposition of CuCO₃ is as follows

CuCO₃ --> CuO + CO₂

molar ratio of CuCO₃ to CO₂ is 1:1

number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol

according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of CuCO₃ decomposes to form 0.364 mol of CO₂

number of CO₂ moles produced - 0.364 mol

therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g

16.02 g of CO₂ produced

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3 years ago

What is the final, balanced equation that is formed by combining these two half reactions?

lara31 [8.8K]

Answer: Balanced equation that is formed by combining these two half reactions is $Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$ .

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, $Cu \rightarrow Cu^{2+} + 2e^{-}$

$NO^{-}_{3} + 2e^{-} + 2H^{+} \rightarrow NO^{-}_{2} + H_{2}O$

On cancelling the common species from both these half-reactions, the complete balanced equation will be as follows.

$Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$

Thus, we can conclude that balanced equation that is formed by combining these two half reactions is $Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$ .

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3 years ago

Which description lists Earth's layers from most superficial to deepest?

Zanzabum

Lithosphere, asthenosfhere , lower mantle

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3 years ago

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