Salt and water are formed
H₃PO₄ + 3KOH = K₃PO₄ + 3H₂O
CH₃COOH + NaOH = CH₃COONa + H₂O
2.5 % w/v ( that means we have 2.5 grams of solute in 100 mL <span>solution )
1.00 mL = 1000 mL therefore:
2.5 g ------------- 100 mL
?? --------------- 1000 mL
1000 x 2.5 / 100 => 25.0 g of NaCl</span>
12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.
Explanation:
Data given:
The air fuel mixture is assumed to be having ideal behaviour
initial volume of gaseous air fuel mixture V1 = 600 ml
initial pressure of gaseous air fuel mixture P1= 1 atm
final volume when piston is removed, V2= 50 ml
final pressure of the gaseous air mixture, P2 = ?
Applying the Boyle's Law,
P1V1 = P2V2
rearranging the equation:
P2 = 
putting the value in the equation,
P2 = 
P2 = 12 atm
the pressure is increased to 12 atm when volume is reduced to 50 ml.
I feel that it is D but I am not 100% sure sadly.
Answer: electrons
Explanation: moving electrons cause momentarily charge
Distribution on molecule. This distribution induces similar distribution to
Adjacent molecule.