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a_sh-v [17]
3 years ago
6

The main types of chemical bonds are ________ and _______ bonds

Chemistry
1 answer:
Musya8 [376]3 years ago
5 0

Answer:

covalent and ionic

Explanation:

covalent is nonmetal+nonmetal

ionic is metal+nonmetal

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Choose a body system and write about what kind of music it would listen to. write 2 sentences for full credit.
Mariulka [41]

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music has also been found to have an effect on learning.

8 0
3 years ago
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What does carbon dioxide absorb the most heat energy
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Should be <span>during deposition.

</span>
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If we wanted to add to the Venn diagram to reflect the Arrhenius acid-base theory, which statements would be MOST appropriate? A
Arlecino [84]

Answer:b

Explanation:

4 0
3 years ago
Which of the following describes metallic character on the periodic table? Question 1 options: A) It increases as you move right
Ilia_Sergeevich [38]

Answer:

D

Explanation:

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3 0
3 years ago
An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

6 0
3 years ago
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