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svp [43]
3 years ago
5

What is 1 + 2 -3 +5 - 10​

Physics
1 answer:
e-lub [12.9K]3 years ago
5 0
-5 is the correct answer for this!
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If your doctor told you that you have strep throat, you could conclude that you are infected with which type of pathogen? A. bac
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You are infected by the streptococcus <em>bacterium</em>.  You will suffer from a sore throat, as well as occasional rubus of the gastric musosa, unrtil you shake that thing.  Shake it now, baby !

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An ideal gas occupies 600 cm3 at 20c. at what temperature will it occupy 1200 cm3 if the pressure remains constant? 10c 40c 100c
Anna11 [10]
ANS : 313℃
You need to use K in this.
To convert​ ℃ to Kelvin (K), add 273.15 to ℃.

5 0
4 years ago
35 miles North 6 feet down 136 MB 85 km SE
pantera1 [17]
The answer is 133 Se
4 0
3 years ago
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A kettle of water contains 1.2 kg of water. Calculate how much energy is required to hear it from water at 10 degrees to its boi
Darya [45]

Answer:

450 kJ

Explanation:

Q = mCΔT

where Q is heat (energy),

m is mass,

C is specific heat capacity,

and ΔT is the temperature change.

Q = (1.2 kg) (4180 J/kg/°C) (100°C − 10°C)

Q = 451,440 J

Q ≈ 450 kJ

6 0
3 years ago
One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories
ch4aika [34]

Answer:

114.92749 keV

Explanation:

r = Radius of trajectory

m = Mass of electron = 9.11\times 10^{-31}\ kg

B = Magnetic field = 0.044 T

q = Charge of electron = 1.6\times 10^{-19}\ C

The centripetal force and the magnetic forces are conserved

m\frac{v^2}{r}=Bqv\\\Rightarrow v=\frac{Bqr}{m}

Velocity of first electron

v=\frac{Bqr_1}{m}\\\Rightarrow v=\frac{0.044\times 1.6\times 10^{-19}\times 0.01}{9.11\times 10^{-31}}\\\Rightarrow v_1=77277716.79473\ m/s

Velocity of second electron

v=\frac{Bqr_2}{m}\\\Rightarrow v_2=\frac{0.044\times 1.6\times 10^{-19}\times 0.024}{9.11\times 10^{-31}}\\\Rightarrow v_2=185466520.30735\ m/s

Total kinetic energy is given by

K=K_1+K_2\\\Rightarrow K=\frac{1}{2}mv_1^2+\frac{1}{2}mv_2^2\\\Rightarrow K=\frac{1}{2}m(v_1^2+v_2^2)\\\Rightarrow K=\frac{1}{2}\times 9.11\times 10^{-31}(77277716.79473^2+185466520.30735^2)\\\Rightarrow K=1.83884\times 10^{-14}\ J

Converting to eV

1\ J=\frac{1}{1.6\times 10^{-19}}\ eV

1.83884\times 10^{-14}\ J=1.83884\times 10^{-14}\times \frac{1}{1.6\times 10^{-19}}\ eV\\ =114927.49\ ev=114.92749\ keV

The energy of incident electron is 114.92749 keV

5 0
4 years ago
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