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Leviafan [203]
3 years ago
7

A 92-kg rugby player running at 7.5 m/s collides in midair with a 112-kg player moving in the opposite direction. After the coll

ision each player has zero velocity.
What was the initial speed of the 112-kg player before the collision?
Physics
1 answer:
madam [21]3 years ago
8 0

By the condition of momentum conservation we can say that since there is no external force along horizontal direction so we will have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

here we know that

m_1 = 92 kg

v_{1i} = 7.5 m/s

m_2 = 112 kg

also we know that

v_{1f} = v_{2f} = 0

now from above equation we have

92(7.5) + 112 v = 0 + 0

now we have

v = 6.16 m/s

so the speed of the other player must be 6.16 m/s

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