A sodium atom can easily lose an electron. What happens to this electron?

What is the pH of a solution that contains 0.009 grams of oxalic acid in 100 mL of water?

tigry1 [53]

Answer:

pH = 3.0 ya that's it......

5 0

3 years ago

An organic compound has the empirical formula C2H4O. what is the compound?

rosijanka [135]

Answer:

The correct answer is - butanoic acid

Explanation:

An empirical formula is the general formula or base formula that is the simplest positive integer ratio of atoms present in a compound. The empirical formula is specific to specific compounds or types of compounds.

Among the given options, the empirical formula C2H4O is butanoic acid as the molecular formula of butanoic acid is - C4H8O2 which is multiple of C2H4O. Other compounds have different than this empirical formula.

3 0

3 years ago

How many molecules OF2 would have a mass of .132 g

BlackZzzverrR [31]

<h3>Answer:</h3>

1.47 × 10²¹ molecules OF₂

<h3>General Formulas and Concepts: </h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

<h3>Explanation: </h3>

Step 1: Define

0.132 g OF₂

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of OF₂ - 16.00 + 2(19.00) = 54.00 g/mol

Step 3: Convert

Set up: $\displaystyle 0.132 \ g \ OF_2(\frac{1 \ mol \ OF_2}{54.00 \ g \ OF_2})(\frac{6.022 \cdot 10^{23} \ molecules \ OF_2}{1 \ mol \ OF_2})$
Divide/Multiply: $\displaystyle 1.47204 \cdot 10^{21} \ molecules \ OF_2$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.47204 × 10²¹ molecules OF₂ ≈ 1.47 × 10²¹ molecules OF₂

3 0

3 years ago

Potassium + Chlorine --> Potassium Chloride

ArbitrLikvidat [17]

Answer:

The balanced equation is 2K(s) + Cl2(g)→2KCl(s)

3 0

3 years ago

Read 2 more answers

Key terms: Reset ____________ anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. ____________ tautomers

iogann1982 [59]

Answer:

Acetylide , Enol ,aldehydes, tautomers, alkynes , Hydroboration, Keto

Explanation:

Reset Acetylide anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. Enol tautomers have an O-H group bonded to a C=C. aldehydes are formed from terminal alkynes with the addition of water using BH3 then H2O2. tautomers are constitutional isomers that differ in the location of a double bond and a hydrogen and exist in an equilibrium with each other. alkynes are compounds that contain a carbon-carbon triple bond. Hydroboration of a terminal alkyne adds BH₂ to the less substituted, terminal carbon. Keto tautomers have a C=O and an additional C-H bond.

3 0

3 years ago