Molar mass is the mass of each element multiplied by subscript, then added together.
So, we’ll do
C = 12g x 12 = 144 g
H = 1g x 22 = 22 g
O = 16g x 11 = 176 g
The total of all of these is the molar mass: 342 g in a mol
The amount of mols of each element in each compound is likely equal to its subscripts.
C = 12 mols
H = 22 mols
O = 11 mols
For the atoms, you’ll multiply each one of the above by Avogadro’s number
Avogadro’s Number: 6.02 x 10^23 atoms/mol
When pure HA is added to the buffer, the buffer component ratio and the pH decrease.
<h3>State and explain the relative change in the pH and in the buffer-component concentration ratio, [NaA]/[HA] for the dissolve of pure HA in the buffer.</h3>
When pure HA is added to the buffer, the buffer component ratio and the pH decrease. The added HA increases the concentrations of NA and HA. However, there is a greater relative increase in the concentration of HA. Hence, the ratio of [NaA]/[HA] decreases, causing the solution to become more acidic.
The capacity of a buffer to withstand pH change is measured. The concentration of the buffer's components namely, the acid and its conjugate base determine this ability. Greater buffer capacity is associated with higher buffer concentration.
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Answer:
To help spread seeds to make more strawberries. Once a person bites into a strawberry some of the seeds fall and help plant new ones.
Explanation:
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Answer:
The correct answer is option c.
Explanation:
Formula used to determine an average atomic mass :
Mass of isotope Sb-121 = 120.904 amu
Fractional abundance of Sb-121 = 57.21% = 0.5721
Mass of isotope Sb-123 = 122.904 amu
Fractional abundance of Sb-123 = 42.79% = 0.4279
Average atomic mass of Sb:
