What is the percent yield for a reaction if we predicted the formation

How many electrons in an atom can have the following quantum

gavmur [86]

The answer for the following question is explained.

Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is one(1).

Explanation:

Here;

n represents the principal quantum number

l represents the Azimuthal quantum number

m represents magnetic quantum number

s represents spin quantum number

n = 5,

l = 2,

m = -2,

s = +1/2

Here, it implies 5d orbital.

In the 5d orbital, 10 electrons.

As the magnetic quantum number is -2, and so it can have 1 electron.

Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is one(1)

7 0

3 years ago

what actually is left over of water once it self ionizes? Like what exactly are the hydrogen and hydroxide ions? Do they remain

GrogVix [38]

The formula for the self ionization of water is 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq)

The hydronium (H₃O⁺) is usually just referred to as a hydrogen ion or a proton (H⁺) and hydroxide (OH⁻) doesn't have another name that I am aware of. These ions do stay in solution. However the concentrations are really small and the equilibrium constant (K(w)) is 1×10⁻¹⁴.

I hope this helps. Let me know if anything is unclear.

5 0

3 years ago

What is the expected value for the heat of sublimation of acetic acid if its heat of fusion is 10.8 kJ/mol and its heat of vapor

Dennis_Churaev [7]

Answer:

35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.

Explanation:

$CH_3COOH(l)\rightarrow CH_3COOH(g)$ ..[1]

Heat of vaporization of acetic acid = $H^o_{vap}=24.3 kJ/mol$

$CH_3COOH(s)\rightarrow CH_3COOH(l)$ ..[2]

Heat of fusion of acetic acid = $H^o_{fus}=10.8 kJ/mol$

Heat of sublimation of acetic acid = $H^o_{sub}=?$

$CH_3COOH(s)\rightarrow CH_3COOH(g)$ ..[3]

[1] + [2] = [3] (Hess's law)

$H^o_{sub}=H^o_{vap}+H^o_{fus}$

$=24.3 kJ/mol+10.8 kJ/mol=35.1 kJ/mol$

35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.

5 0

2 years ago

How many grams are 3.01 × 1023 molecules of CuSO4?

zvonat [6]

Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.

4 0

3 years ago

Is atomic weight a whole number or not a whole number

steposvetlana [31]

Answer:

Atomic mass of an element is not a whole number because It contains isotopes. For example, chlorine has two isotopes 1735Cl and 1737Cl with natural abundances in the approximate ratio of 3:1. Hence, the average atomic mass of chlorine is approximately 35.5 g/mol.

Hope this helps! If so please mark brainliest and rate/heart if it did to help my account out!!

3 0

3 years ago