All categories

3 years ago

Which formula can be used to calculate the molar mass of ammonia (NH3)?

Chemistry

1 answer:

Vesnalui [34]3 years ago

7 0

Answer: The correct answer is Option C.

Explanation:

Molar mass is defined as the sum of the atoms present in a compound each multiplied with the number of atoms present in it.

For a compound $A_xB_y$

The molar mass will be = $[(x\times \text{Molar mass of A})+(y\times \text{Molar mass of B})]$

So, for the given compound $NH_3$ ,

The molar mass will be = $[(1\times \text{Molar mass of Niyrogen})+(3\times \text{Molar mass of Hydrogen})]$

Hence, the correct answer is Option C.

You might be interested in

Help, cant get it. Answers in picture

Aleks04 [339]

Answer:17.0

Explanation:

8 0

3 years ago

You have dissolved 10 g sodium oxide in 200 ml water.calculate concentration of the solution

e-lub [12.9K]

Answer:

0.85 Molar Na2O

Explanation:

Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).

(10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.

Molar is a measure of concentration. It is defined as moles/liter. A 1 M solution contains 1 mole of solute per liter of solvent. [200 ml water = 0.2 Liters water.]

In this case, we have 0.161 moles Na2O in 0.200 L of solvent.

(0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O

8 0

2 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

3 years ago

Read 2 more answers

A strong acid, HA, is added to water. Which statement about the solution is true?

Arturiano [62]

My answer to this question is C

3 0

3 years ago

Structural formula for 4-nonene and fluorine gas

goldenfox [79]

I THINK it's 1,1-Difluorononane, or $C_9H_{18}F_2$ .

6 0

3 years ago

Read 2 more answers