All categories

3 years ago

Which formula can be used to calculate the molar mass of ammonia (NH3)?

Chemistry

1 answer:

Vesnalui [34]3 years ago

7 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Molar mass is defined as the sum of the atoms present in a compound each multiplied with the number of atoms present in it.

For a compound $A_xB_y$

The molar mass will be = $[(x\times \text{Molar mass of A})+(y\times \text{Molar mass of B})]$

So, for the given compound $NH_3$ ,

The molar mass will be = $[(1\times \text{Molar mass of Niyrogen})+(3\times \text{Molar mass of Hydrogen})]$

Hence, the correct answer is Option C.

You might be interested in

The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10-6 M/s.

avanturin [10]

Answer:

The rate would be lower and the concentration of reactants would be lower.

Explanation:

The rate of a chemical reaction depends on the rate constant and the concentration of reactants.

For Ex:

For a reaction experimentally given by A + B ----> C + D

Rate = k[A][B]

where k is the rate constant

[A] = concentration of reactant A

[B] = concentration of reactant B

As the reaction proceeds,the concentration of reactant decrease and concentration of products increase.Rate constant k depends only on temperature and activation energy.Hence it will remain constant throughout the reaction assuming that reaction is carried out at constant temperature and pressure.

Hence rate will depend only on concentration of reactants and hence decrease with decrease in concentration of reactants.

8 0

2 years ago

What is a fibrous root?

Maslowich

I don’t really know

5 0

2 years ago

Read 2 more answers

how many moles of barium hydroxide, Ba(OH2), would be required to react with 117 g hydrogen bromide, HBr?

Kisachek [45]

The moles of Ba(OH)2 that is required to react with 117 HBr is calculated as below

find the moles of HBr used
mass/ molar mass = 117 g/ 80.9 g/mol = 1.446 moles

write the reacting equation

Ba(OH)2 + 2 HBr = BaBr2 + 2 H2O

by use of mole ratio of Ba(OH)2 : HBr which is 1:2 the moles of Ba(OH)2 is therefore
= 1.446 moles x1/2 = 0.723 moles of Ba(OH)2

4 0

3 years ago

Read 2 more answers

Alexa is teaching students to measure and compare the speed of a pencil as it is dropped from different heights

Viefleur [7K]

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ It is because it involves experimentation and observation of the pencil dropping from different heights.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

6 0

3 years ago

Read 2 more answers

A 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the con

inn [45]

Answer:

The equilibrium concentration of I₂ is 0.400 M and HI is 1.20 M, the Keq will be 0.112.

Explanation:

Based on the given information, the equilibrium reaction will be,

2HI (g) ⇔ H₂ (g) + I₂ (g)

It is given that 4.00 mol of HI was filled in a flask of 2.00 L, thus, the concentration of HI will be,

= 4.00 mol/2.00 L

= 2.00 mol/L

Based on the reaction, the initial concentration of 2HI is 2.00, H₂ is 0 and I₂ is O. The change in the concentration of 2HI is -x, H₂ is x and I₂ is x. The equilibrium concentration of 2HI will be 0.200-x, H₂ is x and I₂ is x.

It is given that at equilibrium, the concentration of H₂ or x is 0.400 M.

Now the equilibrium concentration of HI will be,

= 2.00 -2x

= 2.00 - 2 × 0.400

= 1.20 M

The equilibrium concentration of I₂ will be,

I₂ = x

= 0.400 M

The equilibrium constant (Keq) will be,

Keq = [H₂] [I₂] / [HI]²

= (0.400) (0.400) / (1.20)²

= 0.112

Thus, the Keq of the reaction will be 0.112.

5 0

3 years ago