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3 years ago

Which formula can be used to calculate the molar mass of ammonia (NH3)?

Chemistry

1 answer:

Vesnalui [34]3 years ago

7 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Molar mass is defined as the sum of the atoms present in a compound each multiplied with the number of atoms present in it.

For a compound $A_xB_y$

The molar mass will be = $[(x\times \text{Molar mass of A})+(y\times \text{Molar mass of B})]$

So, for the given compound $NH_3$ ,

The molar mass will be = $[(1\times \text{Molar mass of Niyrogen})+(3\times \text{Molar mass of Hydrogen})]$

Hence, the correct answer is Option C.

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2 years ago

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3 years ago

The common laboratory solvent benzene is often used to purify substances dissolved in it. The vapor pressure of benzene , C6H6,

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Answer: Molecular weight of this compound is 387.3g/mol

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

$\frac{p^o-p_s}{p^o}=i\times x_2$

where,

$\frac{p^o-p_s}{p^o}$ = relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

$x_2$ = mole fraction of solute = $\frac{\text {moles of solute}}{\text {total moles}}$

Given : 18.16 g of compound is present in 228.6 g of benzene

moles of solute = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{18.16g}{Mg/mol}$

moles of solvent (benzene) = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{228.6g}{78g/mol}=2.93moles$

$x_2$ = mole fraction of solute = $\frac{\frac{18.16g}{Mg/mol}}{\frac{18.16g}{Mg/mol}+2.93}$

$\frac{73.03-71.88}{73.03}=1\times \frac{\frac{18.16g}{Mg/mol}}{\frac{18.16g}{Mg/mol}+2.93}$

$M=387.3g/mol$

The molecular weight of this compound is 387.3g/mol

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3 years ago