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3 years ago

Where do electrons prefer to spend most of their time ?

Chemistry

2 answers:

zlopas [31]3 years ago

7 0

around the oxygen atom

nordsb [41]3 years ago

6 0

Electrons spend most of their time in between atoms.

Hope this helps,

Davinia.

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At standard temperature and pressure, 1 mole of gas has what volume? A. 2.4 liters B. 22.4 liters C. 42.4 liters D. 76.6 liters

LekaFEV [45]

Answer: B.22.4 liters

Explanation:

When we attribute to a certain fixed mass of a given gas a fixed number of molecules. Avogadro considered that the mass of 36g of oxygen at any temperature and pressure would have a fixed number of molecules to which he called 1 mol of molecules. So by definition 1 mole of molecules would have a number of molecules equal to that present in 36 g of oxygen. The occupied volume by one mole of molecules at a given temperature and pressure is called molar volume and consists in 22,4 Liters. The molar volume matches the Avogadro Hypothesis (created in 1811 by Amedeo Avogadro), where equal volumes of different gases, at the same temperature and pressure, have even number of moles.

8 0

3 years ago

Low tide____.

Fantom [35]

Answer:

i think the answer is A

Explanation:

because in some areas, a regular pattern occurs of one high tide and one low tide each day,

8 0

3 years ago

Read 2 more answers

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

3 years ago

How many grams of Br are in 335g of CaBr2

ASHA 777 [7]

The answer is 267.93 g

Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g

7 0

3 years ago

Convert 5.28 x 1019 molecules of C6H1206 to grams.

nlexa [21]

Answer:

$m=0.0158g$

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

$m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g$

Best regards!

5 0

3 years ago