All categories

3 years ago

Why is it advisable not to look directly at the Sun? Please Give scientific reason for your answer

2 answers:

8 0

Search Results
Featured snippet from the web
This sunlight can flood your retinas, overstimulating the rods and cones that sense light and causing them to release chemicals that can damage the retinas. This condition is known as solar retinopathy, and it can cause permanent eye damage.

OleMash [197]3 years ago

6 0

Hey there!

The sun's UV radiation damages the light receptors of the retina, so we should not look at the sun directly, but during sunrise and sunset the sunlight is coming at us horizontally rather than vertically. It has traveled many miles through the atmosphere to reach our eyes.

Hope this work for you.

You might be interested in

What is the limitation of relative dating?

astraxan [27]

Your not really supposed to date your relative

7 0

3 years ago

ANSWER ASAP

shtirl [24]

5.6 g/ml. That is the density.

5 0

3 years ago

Read 2 more answers

When is a secondary source more helpful than a primary source?

UNO [17]

Answer:

I think the answer is C.

Explanation:

A primary source is a first hand account of an event while a secondary source is a retelling or second hand account meaning as many details will be prevalent.

8 0

2 years ago

Explain how an alpine glacier can change the topography of a mountainous area

igor_vitrenko [27]

<span>An alpine glacier can change the topography of a mountainous area through Glacial Erosion and Glacial Deposition. Glaciers are agents of erosion, it can pick up and carry large rocks and sediments. In the process, a deep cavity or hole can form when the glacier plucks a big rock from where it passed. Glaciers have shaped many Mountain Ranges and have created distinct landforms by its erosion process. In Glacial Deposition, as glaciers melt, it deposits all that it carried and a landform is developed.</span>

7 0

3 years ago

Two point charges are separated by 10 cm, with an attractive force between them of 15 N. Find the force between them when they a

suter [353]

Answer:

(a) the force is 8.876 N

(b) the magnitude of each charge is 4.085 μC

Explanation:

Part (a)

Given;

coulomb's constant, K = 8.99 x 10⁹ N.m²/C²

distance between two charges, r = 10 cm = 0.1 m

force between the two charges, F = 15 N

when the distance between the charges changes to 13 cm (0.13 m)

force between the two charges, F = ?

Apply Coulomb's law;

$F = \frac{Kq_1q_2}{r^2} \\\\let \ Kq_1q_2 = C\\\\F =\frac{C}{r^2} \\\\C = Fr^2\\\\F_1r_1^2 = F_2r_2^2\\\\F_2 =\frac{F_1r_1^2}{r_2^2} \\\\F_2 = \frac{15*0.1^2}{0.13^2} \\\\F_2 = 8.876 \ N$

Part (b)

the magnitude of each charge, if they have equal magnitude

$F = \frac{KQ^2}{r^2}$

where;

F is the force between the charges

K is Coulomb's constant

Q is the charge

r is the distance between the charges

$F = \frac{KQ^2}{r^2} \\\\Q = \sqrt{\frac{Fr^2}{K} } \\\\Q = \sqrt{\frac{15*(0.1)^2}{8.99*10^9} } = 4.085 *10^{-6} \ C\\\\Q = 4.085 \ \mu C$

4 0

4 years ago