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nika2105 [10]
3 years ago
9

A ball is given an initial velocity of 160ft/s straight up. Use g = -32ft/s^2

Physics
1 answer:
horrorfan [7]3 years ago
3 0

Answers:

A) 10 s

B) -64 ft/s

C) 400 ft

D) 336 ft

Explanation:

This described situation is related to vertical motion, and the main equations for this situation are as follows:

y=y_{o}+V_{o}t+\frac{1}{2}gt^{2} (1)

V=V_{o}+gt (2)

V^{2}={V_{o}}^{2}+2gy (3)

Where:

y is the height of the ball at a given time

y_{o}=0 is the initial height of the ball

V_{o}=160 ft/s is the initial velocity of the ball

t is the time  

g=-32 ft/s^{2} is the acceleration due to gravity on Earth (directed downwards)

V is the final velocity of the ball at a given time

Now let's start with the answers:

<h2>A) Total time of the ball in the air</h2>

In this case we will use equation (1) to calculate the total time the ball was in the air (since it was thrown straight up until it hit the ground) with the following condition:

y=0 assuming the initial and the final height is zero

0=0+V_{o}t+\frac{1}{2}gt^{2} (4)

Isolating t:

t=\frac{-2V_{o}}{g} (5)

t=\frac{-2(160 ft/s)}{-32 ft/s^{2}} (6)

Then:

t=10 s (7)

<h2>B) Velocity at 7 s</h2>

In this part we will use equation (2) in order to find the final velocity of the ball when t= 7 s:

V=V_{o}+gt

V=160 ft/s+(-32 ft/s^{2})(7 s) (8)

Hence:

V=-64 ft/s (9)  The negative sign indicates the velocity is directed downwards

<h2>C) Maximum height</h2>

The height of the ball has its maximum value when V=0, just in the moment at the top of its movement, before the begining of the free fall.

In this case we will use equation (3) with the explained condition above:

V^{2}={V_{o}}^{2}+2gy

0={V_{o}}^{2}+2gy (10)

Finding y:

y=\frac{-{V_{o}}^{2}}{2g} (11)

y=\frac{-(160 ft/s)^{2}}{2(-32 ft/s^{2})} (12)

Then:

y=400 ft (12) This is the ball's maximum height

<h2>D) Height at 7 s</h2>

In this part we can use equation (1) for t=7 s:

y=y_{o}+V_{o}t+\frac{1}{2}gt^{2}

y=0+V_{o}t+\frac{1}{2}gt^{2} (13)

y=(160 ft/s)(7s)+\frac{1}{2}(-32 ft/s^{2})(7s)^{2} (14)

Finally:

y=336 ft (15)

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Answer:

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Explanation:

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Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with a mass of 2M when acted upon by a net force of 2F?

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we can say that

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t=time

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since a=(v-u)/t

f=m*a

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a is the acceleration of the object involved

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